Two negative integers are 8 units apart on the number line and have a product of 308. Which equation could be used to determine [tex][tex]$x$[/tex][/tex], the smaller negative integer?

A. [tex][tex]$x^2+8 x-308=0$[/tex][/tex]
B. [tex][tex]$x^2-8 x+308=0$[/tex][/tex]
C. [tex][tex]$x^2+8 x+308=0$[/tex][/tex]
D. [tex][tex]$x^2-8 x-308=0$[/tex][/tex]



Answer :

To determine the correct equation for finding [tex]\( x \)[/tex], the smaller negative integer, given that two negative integers are 8 units apart on the number line and have a product of 308, we can follow these steps:

1. Define the Variables:
- Let [tex]\( x \)[/tex] be the smaller negative integer.
- The larger negative integer will be [tex]\( x + 8 \)[/tex], since they are 8 units apart.

2. Formulate the Relationship:
- The problem states that the product of these two integers is 308. So we can write the equation:
[tex]\[ x \cdot (x + 8) = 308 \][/tex]

3. Expand and Simplify:
- Distribute [tex]\( x \)[/tex] on the left side of the equation:
[tex]\[ x^2 + 8x = 308 \][/tex]

4. Set Up a Standard Quadratic Equation:
- To form a standard quadratic equation, we need to bring all terms to one side of the equation:
[tex]\[ x^2 + 8x - 308 = 0 \][/tex]

5. Verify the Quadratic Equation:
- The correct form of the quadratic equation based on the given conditions is:

[tex]\[ x^2 + 8x - 308 = 0 \][/tex]

Based on this detailed reasoning, the equation that can be used to determine [tex]\( x \)[/tex], the smaller negative integer, is:

[tex]\[ \boxed{x^2 + 8x - 308 = 0} \][/tex]