Let's identify and name the given compounds using the Stock system, which involves identifying the elements and their respective oxidation states:
### Compound a: [tex]\( \text{NaI} \)[/tex]
1. Identify the elements: Sodium (Na) and Iodine (I).
2. Oxidation states: Sodium generally has a +1 oxidation state, and Iodine is -1.
3. Name: Sodium Iodide.
### Compound b: [tex]\( \text{MgS} \)[/tex]
1. Identify the elements: Magnesium (Mg) and Sulfur (S).
2. Oxidation states: Magnesium has a +2 oxidation state, and Sulfur is -2.
3. Name: Magnesium Sulfide.
### Compound c: [tex]\( \text{CaO} \)[/tex]
1. Identify the elements: Calcium (Ca) and Oxygen (O).
2. Oxidation states: Calcium has a +2 oxidation state, and Oxygen is -2.
3. Name: Calcium Oxide.
### Compound d: [tex]\( \text{K}_2\text{S} \)[/tex]
1. Identify the elements: Potassium (K) and Sulfur (S).
2. Oxidation states: Potassium has a +1 oxidation state, and Sulfur is -2.
3. Name: Potassium Sulfide.
### Compound e: [tex]\( \text{CuBr} \)[/tex]
1. Identify the elements: Copper (Cu) and Bromine (Br).
2. Oxidation states: Copper can have multiple oxidation states, but in this case, it has a +1 state, and Bromine is -1.
3. Name: Copper(I) Bromide.
### Compound f: [tex]\( \text{FeCl}_2 \)[/tex]
1. Identify the elements: Iron (Fe) and Chlorine (Cl).
2. Oxidation states: Iron can have multiple oxidation states; in this case, it is +2, and each Chlorine is -1.
3. Name: Iron(II) Chloride.
So, the names of the compounds are:
- a: Sodium Iodide
- b: Magnesium Sulfide
- c: Calcium Oxide
- d: Potassium Sulfide
- e: Copper(I) Bromide
- f: Iron(II) Chloride
