Solve.

[tex]\[ 2a + 4 \ \textgreater \ 12 \][/tex]

A. [tex]\(\{a \mid a \ \textgreater \ 2\}\)[/tex]
B. [tex]\(\{a \mid a \ \textgreater \ 4\}\)[/tex]
C. [tex]\(\{a \mid a \ \textgreater \ 8\}\)[/tex]
D. [tex]\(\{a \mid a \ \textgreater \ 10\}\)[/tex]