A cylindrical container has a base area of [tex][tex]$100 \, \text{m}^2$[/tex][/tex] and is [tex][tex]$12 \, \text{m}$[/tex][/tex] high. If the container is one-third filled with water, what's the volume of the water in the container?

A) [tex][tex]$1,200 \, \text{m}^3$[/tex][/tex]
B) [tex][tex]$300 \, \text{m}^3$[/tex][/tex]
C) [tex][tex]$600 \, \text{m}^3$[/tex][/tex]
D) [tex][tex]$400 \, \text{m}^3$[/tex][/tex]



Answer :

To determine the volume of water in a cylindrical container, we start by calculating the total volume of the container and then use the given fraction to find the volume of the water.

1. Identify the given values:
- Base area of the cylinder, [tex]\( A = 100 \, \text{m}^2 \)[/tex]
- Height of the cylinder, [tex]\( h = 12 \, \text{m} \)[/tex]

2. Calculate the total volume of the cylinder:
The formula for the volume [tex]\( V \)[/tex] of a cylinder is given by:
[tex]\[ V = \text{base area} \times \text{height} \][/tex]
Substituting the given values:
[tex]\[ V = 100 \, \text{m}^2 \times 12 \, \text{m} = 1200 \, \text{m}^3 \][/tex]

3. Determine the volume of the water:
The container is one-third filled with water. Hence, the volume of water [tex]\( V_{\text{water}} \)[/tex] is:
[tex]\[ V_{\text{water}} = \frac{1}{3} \times V \][/tex]
Substituting the total volume calculated earlier:
[tex]\[ V_{\text{water}} = \frac{1}{3} \times 1200 \, \text{m}^3 = 400 \, \text{m}^3 \][/tex]

Therefore, the volume of the water in the container is [tex]\( \mathbf{400 \, m^3} \)[/tex].

The correct answer is [tex]\( \boxed{400 \, \text{m}^3} \)[/tex].