Let's solve each of the given problems one by one and match them with their corresponding answers.
### Problem 1: [tex]\(\frac{3}{11} - \frac{8}{11}\)[/tex]
To solve this problem, we need to subtract [tex]\(\frac{8}{11}\)[/tex] from [tex]\(\frac{3}{11}\)[/tex]:
[tex]\[
\frac{3}{11} - \frac{8}{11} = \frac{3 - 8}{11} = \frac{-5}{11}
\][/tex]
Therefore, [tex]\(\frac{3}{11} - \frac{8}{11} = -\frac{5}{11}\)[/tex].
Next, we match this result with the provided answers:
- The result [tex]\(-\frac{5}{11}\)[/tex] corresponds to answer [tex]\(e\)[/tex]: [tex]\(-\frac{5}{11}\)[/tex].
### Problem 2: [tex]\(\frac{6}{11} - \frac{2}{11}\)[/tex]
To solve this problem, we need to subtract [tex]\(\frac{2}{11}\)[/tex] from [tex]\(\frac{6}{11}\)[/tex]:
[tex]\[
\frac{6}{11} - \frac{2}{11} = \frac{6 - 2}{11} = \frac{4}{11}
\][/tex]
Therefore, [tex]\(\frac{6}{11} - \frac{2}{11} = \frac{4}{11}\)[/tex].
Next, we match this result with the provided answers:
- The result [tex]\(\frac{4}{11}\)[/tex] corresponds to answer [tex]\(c\)[/tex]: [tex]\(\frac{4}{11}\)[/tex].
### Problem 3: [tex]\(\frac{1}{11} + \frac{5}{11}\)[/tex]
To solve this problem, we need to add [tex]\(\frac{1}{11}\)[/tex] to [tex]\(\frac{5}{11}\)[/tex]:
[tex]\[
\frac{1}{11} + \frac{5}{11} = \frac{1 + 5}{11} = \frac{6}{11}
\][/tex]
Therefore, [tex]\(\frac{1}{11} + \frac{5}{11} = \frac{6}{11}\)[/tex].
Next, we match this result with the provided answers:
- The result [tex]\(\frac{6}{11}\)[/tex] corresponds to answer [tex]\(b\)[/tex]: [tex]\(\frac{6}{11}\)[/tex].
### Summary
Now we have matched the problems with the corresponding answers:
1. [tex]\(\frac{3}{11} - \frac{8}{11} = -\frac{5}{11}\)[/tex] corresponds to answer [tex]\(e\)[/tex].
2. [tex]\(\frac{6}{11} - \frac{2}{11} = \frac{4}{11}\)[/tex] corresponds to answer [tex]\(c\)[/tex].
3. [tex]\(\frac{1}{11} + \frac{5}{11} = \frac{6}{11}\)[/tex] corresponds to answer [tex]\(b\)[/tex].
Therefore, the correct mapping is:
[tex]\[
\begin{array}{ll}
\text{Problem 1} & \rightarrow \text{Answer e: } -\frac{5}{11} \\
\text{Problem 2} & \rightarrow \text{Answer c: } \frac{4}{11} \\
\text{Problem 3} & \rightarrow \text{Answer b: } \frac{6}{11} \\
\end{array}
\][/tex]
