Solve for [tex][tex]$x$[/tex][/tex]. If there are multiple solutions, enter them as a list of values separated by commas. If there are no solutions, enter None.

[tex]\[
\frac{3}{x+11} - \frac{5}{x-5} = 1
\][/tex]



Answer :

To solve the equation [tex]\(\frac{3}{x+11} - \frac{5}{x-5} = 1\)[/tex], we can follow these steps:

1. Find a common denominator: The common denominator for the fractions [tex]\(\frac{3}{x+11}\)[/tex] and [tex]\(\frac{5}{x-5}\)[/tex] is [tex]\((x+11)(x-5)\)[/tex].
2. Rewrite each term with the common denominator:

[tex]\[ \frac{3}{x+11} = \frac{3(x-5)}{(x+11)(x-5)} \][/tex]

[tex]\[ \frac{5}{x-5} = \frac{5(x+11)}{(x-5)(x+11)} \][/tex]

3. Set up the equation with the common denominator:

[tex]\[ \frac{3(x-5) - 5(x+11)}{(x+11)(x-5)} = 1 \][/tex]

4. Combine the numerators and set the equation equal to 1:

[tex]\[ \frac{3(x-5) - 5(x+11)}{(x+11)(x-5)} = 1 \][/tex]

5. Eliminate the denominator by multiplying both sides of the equation by [tex]\((x+11)(x-5)\)[/tex]:

[tex]\[ 3(x-5) - 5(x+11) = (x+11)(x-5) \][/tex]

6. Simplify the left side of the equation:

[tex]\[ 3x - 15 - 5x - 55 = (x+11)(x-5) \][/tex]

Combining like terms:

[tex]\[ -2x - 70 = (x+11)(x-5) \][/tex]

7. Expand the right side of the equation:

[tex]\[ -2x - 70 = x^2 - 5x + 11x - 55 \][/tex]

Simplifying:

[tex]\[ -2x - 70 = x^2 + 6x - 55 \][/tex]

8. Set up the quadratic equation by moving all terms to one side:

[tex]\[ x^2 + 6x - 55 + 2x + 70 = 0 \][/tex]

Simplifying:

[tex]\[ x^2 + 8x + 15 = 0 \][/tex]

9. Solve the quadratic equation [tex]\(x^2 + 8x + 15 = 0\)[/tex] by factoring:

[tex]\[ (x + 3)(x + 5) = 0 \][/tex]

10. Find the roots of the factored equation:

[tex]\[ x + 3 = 0 \quad \text{or} \quad x + 5 = 0 \][/tex]

Solving these:

[tex]\[ x = -3 \quad \text{or} \quad x = -5 \][/tex]

So, the solutions to the equation [tex]\(\frac{3}{x+11} - \frac{5}{x-5} = 1\)[/tex] are:

[tex]\[ \boxed{-5, -3} \][/tex]