Solve for [tex][tex]$y$[/tex][/tex].

[tex]\[
\begin{array}{r}
2y - 8x = 20 \\
y = [?]x + \square
\end{array}
\][/tex]



Answer :

To solve for [tex]\( y \)[/tex] in the given equation [tex]\( 2y - 8x = 20 \)[/tex], follow these steps:

1. Isolate the term with [tex]\( y \)[/tex]:
Start by moving the term with [tex]\( x \)[/tex] to the other side of the equation.
[tex]\[ 2y = 8x + 20 \][/tex]

2. Solve for [tex]\( y \)[/tex]:
Now, divide every term in the equation by 2 to isolate [tex]\( y \)[/tex].
[tex]\[ y = \frac{8x + 20}{2} \][/tex]

3. Simplify the equation:
Perform the division for each term inside the parenthesis.
[tex]\[ y = 4x + 10 \][/tex]

Therefore, the equation in the form [tex]\( y = mx + b \)[/tex] is:
[tex]\[ y = 4x + 10 \][/tex]

So, the coefficient of [tex]\( x \)[/tex] is [tex]\( 4 \)[/tex] and the constant term is [tex]\( 10 \)[/tex].