Answer :
Sure, let's break down the given arithmetic expression step by step:
[tex]\[ \begin{array}{l} 1+1+1+1 \\ +1+1+1+ \\ 1+1+1+1 \\ +1 \times 0 + 1 = ? \end{array} \][/tex]
First, we need to handle the multiplication operation first, as per the order of operations (PEMDAS/BODMAS).
So, the term [tex]\(1 \times 0\)[/tex] needs to be calculated first:
[tex]\[ 1 \times 0 = 0 \][/tex]
Next, we substitute this result back into the original expression:
[tex]\[ 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 0 + 1 \][/tex]
Now, we sum up all the remaining terms:
[tex]\[ 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 0 + 1 \][/tex]
Let's count the number of ones and zeros in the expression. The expression consists of twelve 1's and one 0. Adding these together:
[tex]\[ 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 0 + 1 = 12 \][/tex]
Therefore, the result of the expression is:
[tex]\[ \boxed{12} \][/tex]
[tex]\[ \begin{array}{l} 1+1+1+1 \\ +1+1+1+ \\ 1+1+1+1 \\ +1 \times 0 + 1 = ? \end{array} \][/tex]
First, we need to handle the multiplication operation first, as per the order of operations (PEMDAS/BODMAS).
So, the term [tex]\(1 \times 0\)[/tex] needs to be calculated first:
[tex]\[ 1 \times 0 = 0 \][/tex]
Next, we substitute this result back into the original expression:
[tex]\[ 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 0 + 1 \][/tex]
Now, we sum up all the remaining terms:
[tex]\[ 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 0 + 1 \][/tex]
Let's count the number of ones and zeros in the expression. The expression consists of twelve 1's and one 0. Adding these together:
[tex]\[ 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 0 + 1 = 12 \][/tex]
Therefore, the result of the expression is:
[tex]\[ \boxed{12} \][/tex]
