Answered

Consider the substances hydrogen [tex][tex]$\left( H_2\right)$[/tex][/tex], fluorine [tex][tex]$\left( F_2\right)$[/tex][/tex], and hydrogen fluoride [tex][tex]$( HF )$[/tex][/tex]. Based on their molecular structures, how does the boiling point of [tex][tex]$HF$[/tex][/tex] compare with the boiling points of [tex][tex]$H_2$[/tex][/tex] and [tex][tex]$F_2$[/tex][/tex]?

The boiling point of [tex][tex]$HF$[/tex][/tex] is [tex][tex]$\square$[/tex][/tex] the boiling point of [tex][tex]$H_2$[/tex][/tex], and it is [tex][tex]$\square$[/tex][/tex] the boiling point of [tex][tex]$F_2$[/tex][/tex].



Answer :

GinnyAnswer
Let's consider the boiling points of hydrogen ([tex]\(H_2\)[/tex]), fluorine ([tex]\(F_2\)[/tex]), and hydrogen fluoride ([tex]\(HF\)[/tex]).

1. The boiling point of hydrogen ([tex]\(H_2\)[/tex]) is [tex]\(-252.87^\circ C\)[/tex].
2. The boiling point of fluorine ([tex]\(F_2\)[/tex]) is [tex]\(-188.11^\circ C\)[/tex].
3. The boiling point of hydrogen fluoride ([tex]\(HF\)[/tex]) is [tex]\(19.5^\circ C\)[/tex].

Next, we compare the boiling point of [tex]\(HF\)[/tex] with each of the other two substances.

1. Comparing [tex]\(HF\)[/tex] and [tex]\(H_2\)[/tex]: The boiling point of [tex]\(HF\)[/tex] ( [tex]\(19.5^\circ C\)[/tex]) is higher than the boiling point of [tex]\(H_2\)[/tex] ([tex]\(-252.87^\circ C\)[/tex]).
2. Comparing [tex]\(HF\)[/tex] and [tex]\(F_2\)[/tex]: The boiling point of [tex]\(HF\)[/tex] ([tex]\(19.5^\circ C\)[/tex]) is higher than the boiling point of [tex]\(F_2\)[/tex] ([tex]\(-188.11^\circ C\)[/tex]).

Based on these comparisons, we conclude:

The boiling point of [tex]\(HF\)[/tex] is higher than the boiling point of [tex]\(H_2\)[/tex], and it is higher than the boiling point of [tex]\(F_2\)[/tex].

So, the final correct answer should be:

The boiling point of [tex]\(HF\)[/tex] is higher than the boiling point of [tex]\(H_2\)[/tex], and it is higher than the boiling point of [tex]\(F_2\)[/tex].

Other Questions