Answer :
To solve the problem of how much Charlie can spend on each sandwich, we need to determine an inequality that represents his budget constraints and find the maximum price per sandwich.
Let's break it down step by step:
1. Identify the Variables and Setup the Inequality:
- Charlie wants to buy 5 sandwiches, each costing [tex]\( x \)[/tex] dollars.
- He also needs to buy a [tex]$3 kid's meal. - He has a total of $[/tex]28 to spend.
We can write the total cost of the sandwiches and the kid's meal as:
[tex]\[ 5x + 3 \][/tex]
This total cost must be less than or equal to Charlie's total amount of money ([tex]$28): \[ 5x + 3 \leq 28 \] 2. Solve the Inequality: - First, subtract the cost of the kid's meal from the total amount: \[ 5x + 3 \leq 28 \implies 5x \leq 28 - 3 \implies 5x \leq 25 \] - Next, divide by the number of sandwiches (5) to solve for \( x \): \[ x \leq \frac{25}{5} \implies x \leq 5 \] Thus, Charlie can spend at most \$[/tex]5 on each sandwich.
3. Selection of the Answers:
- For the inequality that models this situation, we look for the inequality [tex]\( 5x + 3 \leq 28 \)[/tex], which is option F.
- The correct answer for the price per sandwich is [tex]\( \$5 \)[/tex] or less, which is option B.
Therefore, the correct answers are:
- Inequality: [tex]\( 5x + 3 \leq 28 \)[/tex] (Option F)
- Answer: [tex]\( \$5 \)[/tex] or less (Option B)
Let's break it down step by step:
1. Identify the Variables and Setup the Inequality:
- Charlie wants to buy 5 sandwiches, each costing [tex]\( x \)[/tex] dollars.
- He also needs to buy a [tex]$3 kid's meal. - He has a total of $[/tex]28 to spend.
We can write the total cost of the sandwiches and the kid's meal as:
[tex]\[ 5x + 3 \][/tex]
This total cost must be less than or equal to Charlie's total amount of money ([tex]$28): \[ 5x + 3 \leq 28 \] 2. Solve the Inequality: - First, subtract the cost of the kid's meal from the total amount: \[ 5x + 3 \leq 28 \implies 5x \leq 28 - 3 \implies 5x \leq 25 \] - Next, divide by the number of sandwiches (5) to solve for \( x \): \[ x \leq \frac{25}{5} \implies x \leq 5 \] Thus, Charlie can spend at most \$[/tex]5 on each sandwich.
3. Selection of the Answers:
- For the inequality that models this situation, we look for the inequality [tex]\( 5x + 3 \leq 28 \)[/tex], which is option F.
- The correct answer for the price per sandwich is [tex]\( \$5 \)[/tex] or less, which is option B.
Therefore, the correct answers are:
- Inequality: [tex]\( 5x + 3 \leq 28 \)[/tex] (Option F)
- Answer: [tex]\( \$5 \)[/tex] or less (Option B)
