Use technology to graph the polynomial function below, then select its end behaviors.

[tex]f(x) = x^2(x-1)(x+3)(x-2)[/tex]

A. As [tex]x \rightarrow -\infty, f(x) \rightarrow -\infty[/tex]. As [tex]x \rightarrow \infty, f(x) \rightarrow -\infty[/tex].
B. As [tex]x \rightarrow -\infty, f(x) \rightarrow \infty[/tex]. As [tex]x \rightarrow \infty, f(x) \rightarrow -\infty[/tex].
C. As [tex]x \rightarrow -\infty, f(x) \rightarrow \infty[/tex]. As [tex]x \rightarrow \infty, f(x) \rightarrow \infty[/tex].
D. As [tex]x \rightarrow -\infty, f(x) \rightarrow -\infty[/tex]. As [tex]x \rightarrow \infty, f(x) \rightarrow \infty[/tex].



Answer :

To determine the end behavior of the polynomial function [tex]\( f(x) = x^2(x-1)(x+3)(x-2) \)[/tex], we will analyze its leading term and degree.

### Step-by-Step Analysis:

1. Expand the Polynomial:
The function [tex]\( f(x) = x^2(x-1)(x+3)(x-2) \)[/tex] consists of products of four factors.

Let's first identify its leading term and degree:
[tex]\[ f(x) = x^2(x-1)(x+3)(x-2) \][/tex]

2. Degree of the Polynomial:
- The degree of [tex]\( x^2 \)[/tex] is 2.
- The degree of [tex]\( (x-1) \)[/tex] is 1.
- The degree of [tex]\( (x+3) \)[/tex] is 1.
- The degree of [tex]\( (x-2) \)[/tex] is 1.

Adding these together gives us the total degree of the polynomial:
[tex]\[ \text{Degree} = 2 + 1 + 1 + 1 = 5 \][/tex]
The polynomial is of degree 5, which means it is an odd-degree polynomial.

3. Leading Term:
When expanded, the leading term comes from the product of the highest degree terms in each of the factors:
[tex]\[ x^2 \cdot x \cdot x \cdot x = x^{5} \][/tex]
So, the leading term is [tex]\( x^5 \)[/tex].

4. End Behavior:
For a polynomial of the form [tex]\( ax^n \)[/tex]:

- If [tex]\( n \)[/tex] is odd, and [tex]\( a \)[/tex] (the leading coefficient) is positive, then as [tex]\( x \to \infty \)[/tex], [tex]\( f(x) \to \infty \)[/tex], and as [tex]\( x \to -\infty \)[/tex], [tex]\( f(x) \to -\infty \)[/tex].
- If [tex]\( n \)[/tex] is odd and [tex]\( a \)[/tex] is negative, the end behaviors would be reversed.

In our case, the leading coefficient is positive (implicitly 1 in [tex]\( x^5 \)[/tex]) since there are no negative signs involved in the expansion of [tex]\( x^5 \)[/tex].

Therefore, the end behavior follows:
[tex]\[ \begin{cases} \text{As } x \rightarrow \infty, f(x) \rightarrow \infty.\quad (\text{since the leading term } x^5 \text{ dominates})\\ \text{As } x \rightarrow -\infty, f(x) \rightarrow -\infty. \end{cases} \][/tex]

### Conclusion:
The end behaviors of the polynomial function [tex]\( f(x) = x^2(x-1)(x+3)(x-2) \)[/tex] are:
[tex]\[ \boxed{\text{As } x \rightarrow -\infty, f(x) \rightarrow -\infty. \text{ As } x \rightarrow \infty, f(x) \rightarrow \infty.} \][/tex]