Answer :

Sure, let's solve the expression [tex]\( a^2 - b^2 - 2bc - c^2 \)[/tex] step by step.

Let's assume the following values for the variables:
- [tex]\( a = 3 \)[/tex]
- [tex]\( b = 2 \)[/tex]
- [tex]\( c = 1 \)[/tex]

First, we evaluate each term in the expression:

1. Calculate [tex]\( a^2 \)[/tex]:
[tex]\[ a^2 = 3^2 = 9 \][/tex]

2. Calculate [tex]\( b^2 \)[/tex]:
[tex]\[ b^2 = 2^2 = 4 \][/tex]

3. Calculate [tex]\( 2bc \)[/tex]:
[tex]\[ 2bc = 2 \cdot 2 \cdot 1 = 4 \][/tex]

4. Calculate [tex]\( c^2 \)[/tex]:
[tex]\[ c^2 = 1^2 = 1 \][/tex]

Next, substitute these values into the expression:
[tex]\[ a^2 - b^2 - 2bc - c^2 \][/tex]
[tex]\[ = 9 - 4 - 4 - 1 \][/tex]

Finally, combine the terms:
[tex]\[ 9 - 4 - 4 - 1 = 0 \][/tex]

So, the value of the expression [tex]\( a^2 - b^2 - 2bc - c^2 \)[/tex] when [tex]\( a = 3 \)[/tex], [tex]\( b = 2 \)[/tex], and [tex]\( c = 1 \)[/tex] is 0.