Label the number line with intervals of 1 unit.

1. Label 0 at the correct spot on the number line.
2. Label the point plotted to the right of 0.
3. Label the point plotted to the left of 0.

Use this list of numbers to answer the following questions:
[tex]\[ 4, -2, \frac{2}{3}, -1.8, 16, 3.2, -\frac{5}{4} \][/tex]



Answer :

Alright! Let's break down the steps to solve the problem:

### Step 1: List the numbers
First, we'll list the numbers given:
[tex]\[ 4, -2, \frac{2}{3}, -1.8, 16, 3.2, -\frac{5}{4} \][/tex]

### Step 2: Separate the numbers into positive and negative values

- Positive numbers: [tex]\( 4, \frac{2}{3}, 16, 3.2 \)[/tex]
- Negative numbers: [tex]\( -2, -1.8, -\frac{5}{4} \)[/tex]

### Step 3: Find the key points
1. Label 0 on the number line:
- This is straightforward; '0' is our reference point.

2. Find the point to the right of 0 (minimum positive number):
- We have to identify the smallest positive number in the positive list: [tex]\( 4, \frac{2}{3}, 16, 3.2 \)[/tex]
- The minimum value among these is [tex]\( \frac{2}{3} \)[/tex].

3. Find the point to the left of 0 (maximum negative number):
- We need to determine the largest (closest to zero) negative number: [tex]\( -2, -1.8, -\frac{5}{4} \)[/tex]
- The maximum value among these is [tex]\( -1.25 \)[/tex] (i.e., [tex]\( -\frac{5}{4} \)[/tex]).

### Step 4: Label the key points on the number line
- '0' is labeled at its reference position.
- The minimum positive number [tex]\( \frac{2}{3} \)[/tex] is labeled to the right of 0.
- The maximum negative number [tex]\( -1.25 \)[/tex] is labeled to the left of 0.

### Summary of the labeled points:
- 0 at the reference point.
- [tex]\( \frac{2}{3} \)[/tex] to the right of 0.
- [tex]\( -1.25 \)[/tex] (i.e., [tex]\( -\frac{5}{4} \)[/tex]) to the left of 0.

This is how you can label these points on a number line with intervals of 1 unit.