The outcome 2, 2, 0 has which sample mean and probability? (Assume that the outcome of each trial is independent.)

A. [tex]\bar{x} = \frac{4}{3}, p = 0.025[/tex]
B. [tex]\bar{x} = \frac{4}{3}, p = 0.05[/tex]
C. [tex]8 = 4, p = 0.025[/tex]



Answer :

To determine the sample mean and the corresponding probability for the outcome [tex]\( (2, 2, 0) \)[/tex], let's work through the problem step by step.

1. Calculate the Sample Mean:
The sample mean of a set of outcomes is found by summing all the outcomes and then dividing by the number of outcomes. For the outcome [tex]\( (2, 2, 0) \)[/tex]:

[tex]\[ \text{Sample Mean} = \frac{2 + 2 + 0}{3} = \frac{4}{3} \][/tex]

2. Compare the Sample Mean with Given Values:
We are provided with three sets of sample means and probabilities:

1. [tex]\(\varepsilon = \frac{4}{3}, p = 0.025\)[/tex]
2. [tex]\(\bar{x} = \frac{4}{3}, p = 0.05\)[/tex]
3. [tex]\(8 = 4, p = 0.025\)[/tex]

Among these, we need to find which set of sample mean matches our calculated sample mean.

Our calculated sample mean is [tex]\(\frac{4}{3} = 1.3333333333333333\)[/tex].

3. Identify the Matching Probability:
Comparing our calculated sample mean (1.3333333333333333) to the values in the provided sets, we see:

- [tex]\(\varepsilon = \frac{4}{3}, p = 0.025\)[/tex] matches
- [tex]\(\bar{x} = \frac{4}{3}, p = 0.05\)[/tex] also matches
- [tex]\(8 = 4, p = 0.025\)[/tex] does not make sense as a sample mean.

It appears that both [tex]\(\varepsilon = \frac{4}{3}\)[/tex] and [tex]\(\bar{x} = \frac{4}{3}\)[/tex] correspond to our calculated sample mean. Since both provide matching sample means, the lowest probability of [tex]\(0.025\)[/tex] associated with [tex]\(\varepsilon\)[/tex] should be used.

Thus, for the outcome [tex]\((2, 2, 0)\)[/tex]:
- The sample mean is [tex]\(1.3333333333333333\)[/tex].
- The corresponding probability is [tex]\(0.025\)[/tex].