Certainly! Let's perform the long division of 4879 by 15 step-by-step:
1. Start with the leftmost digit of the dividend. Since 15 does not go into 4 (the first digit), we consider the first two digits, which are 48.
How many times can 15 go into 48?
- [tex]\( 15 \times 3 = 45 \)[/tex]
- [tex]\( 15 \times 4 = 60 \)[/tex] (This is too large)
So, 15 goes into 48 three times (3). Write 3 above the 8 as the first digit of our quotient.
2. Subtract [tex]\( 3 \times 15 = 45 \)[/tex] from 48:
[tex]\[
48 - 45 = 3
\][/tex]
3. Bring down the next digit, which is 7. This makes the new number to consider 37.
How many times can 15 go into 37?
- [tex]\( 15 \times 2 = 30 \)[/tex]
- [tex]\( 15 \times 3 = 45 \)[/tex] (This is too large)
So, 15 goes into 37 two times (2). Write 2 next to the 3 in the quotient.
4. Subtract [tex]\( 2 \times 15 = 30 \)[/tex] from 37:
[tex]\[
37 - 30 = 7
\][/tex]
5. Bring down the next digit, which is 9. This makes the new number to consider 79.
How many times can 15 go into 79?
- [tex]\( 15 \times 5 = 75 \)[/tex]
- [tex]\( 15 \times 6 = 90 \)[/tex] (This is too large)
So, 15 goes into 79 five times (5). Write 5 next to the 32 in the quotient.
6. Subtract [tex]\( 5 \times 15 = 75 \)[/tex] from 79:
[tex]\[
79 - 75 = 4
\][/tex]
Since there are no more digits to bring down, we stop here.
The quotient of [tex]\( 4879 \div 15 \)[/tex] is 325, and the remainder is 4.
So, the final answer is:
[tex]\[
4879 \div 15 = 325 \quad \text{with a remainder of} \quad 4.
\][/tex]
In terms of division:
[tex]\[
4879 \div 15 = 325 \, R4
\][/tex]
