A line passes through the point [tex][tex]$(-6, 8)$[/tex][/tex] and has a slope of [tex][tex]$\frac{3}{2}$[/tex][/tex].

Write an equation in point-slope form for this line.



Answer :

Sure! To write the equation of a line in point-slope form, we use the formula:

[tex]\[ y - y_1 = m(x - x_1) \][/tex]

where [tex]\((x_1, y_1)\)[/tex] is a point on the line and [tex]\( m \)[/tex] is the slope of the line.

1. Identify the given point and the slope:
- The given point is [tex]\((-6, 8)\)[/tex], so [tex]\( x_1 = -6 \)[/tex] and [tex]\( y_1 = 8 \)[/tex].
- The given slope is [tex]\( m = \frac{3}{2} \)[/tex].

2. Substitute the values into the point-slope form equation:

[tex]\[ y - y_1 = m(x - x_1) \][/tex]

Substitute [tex]\( x_1 = -6 \)[/tex], [tex]\( y_1 = 8 \)[/tex], and [tex]\( m = \frac{3}{2} \)[/tex]:

[tex]\[ y - 8 = \frac{3}{2}(x - (-6)) \][/tex]

3. Simplify the equation (if necessary):
- Notice that [tex]\( x - (-6) \)[/tex] simplifies to [tex]\( x + 6 \)[/tex].

So, the equation in point-slope form is:

[tex]\[ y - 8 = \frac{3}{2}(x + 6) \][/tex]

Alternatively, expressing with decimal multiplication:

[tex]\[ y - 8 = 1.5(x + 6) \][/tex]

Thus, the point-slope form of the equation for the line passing through the point [tex]\((-6, 8)\)[/tex] with a slope of [tex]\(\frac{3}{2}\)[/tex] is:

[tex]\[ y - 8 = 1.5(x + 6) \][/tex]

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