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Complete the following for the compound iron(III) sulfate.

[tex]\[ \text{formula} = \text{Fe}_2\left(\text{SO}_4\right)_3 \][/tex]

\begin{tabular}{|c|c|}
\hline
\text{Atom} & \text{Number in Formula} \\
\hline
Iron (Fe) & 2 \\
\hline
Sulfur (S) & 3 \\
\hline
Oxygen (O) & 12 \\
\hline
\end{tabular}



Answer :

GinnyAnswer
Let's analyze the chemical formula for iron(III) sulfate, [tex]\( Fe_2(SO_4)_3 \)[/tex], to determine the number of each type of atom contained within one formula unit of the compound.

1. Iron (Fe) atoms:
- The subscript immediately following the Fe element indicates that there are 2 iron atoms in each formula unit.
- Therefore, the number of iron atoms is [tex]\( 2 \)[/tex].

2. Sulfate (SO_4) groups:
- The formula includes the sulfate group [tex]\((SO_4)\)[/tex], and the subscript outside the parentheses is 3. This indicates that there are 3 sulfate groups in each formula unit of iron(III) sulfate.

3. Sulfur (S) atoms:
- Each sulfate group contains 1 sulfur atom [tex]\((S)\)[/tex].
- Since there are 3 sulfate groups, the total number of sulfur atoms is [tex]\( 3 \times 1 = 3 \)[/tex].

4. Oxygen (O) atoms:
- Each sulfate group contains 4 oxygen atoms [tex]\((O)\)[/tex].
- Since there are 3 sulfate groups, the total number of oxygen atoms is [tex]\( 3 \times 4 = 12 \)[/tex].

Putting this all together, we fill in the table as follows:

[tex]\[ \begin{tabular}{|c|c|} \hline \text{atom} & \text{number in formula} \\ \hline \text{iron} & 2 \\ \hline \text{ sulfur} & 3 \\ \hline \text{oxygen} & 12 \\ \hline \end{tabular} \][/tex]

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