Answer :

To determine which number is a multiple of both 6 and 8 from the given list of numbers (18, 2, 3, 24), we need to check if each number can be divided evenly by both 6 and 8.

1. First Number: 18
- Check if 18 is a multiple of 6:
- [tex]\(18 \div 6 = 3\)[/tex] (which is an integer, so 18 is a multiple of 6)
- Check if 18 is a multiple of 8:
- [tex]\(18 \div 8 = 2.25\)[/tex] (which is not an integer, so 18 is not a multiple of 8)

Since 18 is not a multiple of both 6 and 8, we move on to the next number.

2. Second Number: 2
- Check if 2 is a multiple of 6:
- [tex]\(2 \div 6 = 0.3333\)[/tex] (which is not an integer, so 2 is not a multiple of 6)
- Check if 2 is a multiple of 8:
- [tex]\(2 \div 8 = 0.25\)[/tex] (which is not an integer, so 2 is not a multiple of 8)

Since 2 is not a multiple of both 6 and 8, we move on to the next number.

3. Third Number: 3
- Check if 3 is a multiple of 6:
- [tex]\(3 \div 6 = 0.5\)[/tex] (which is not an integer, so 3 is not a multiple of 6)
- Check if 3 is a multiple of 8:
- [tex]\(3 \div 8 = 0.375\)[/tex] (which is not an integer, so 3 is not a multiple of 8)

Since 3 is not a multiple of both 6 and 8, we move on to the next number.

4. Fourth Number: 24
- Check if 24 is a multiple of 6:
- [tex]\(24 \div 6 = 4\)[/tex] (which is an integer, so 24 is a multiple of 6)
- Check if 24 is a multiple of 8:
- [tex]\(24 \div 8 = 3\)[/tex] (which is an integer, so 24 is a multiple of 8)

Since 24 is a multiple of both 6 and 8, it satisfies the condition.

Therefore, the number that is a multiple of both 6 and 8 from the given list is 24.