Question 11 (5 points)

Solve [tex]e^{-x}=e^{2x+6}[/tex]

A. [tex]x=2[/tex]
B. [tex]x=4[/tex]
C. [tex]x=-4[/tex]
D. [tex]x=-2[/tex]



Answer :

To solve the equation [tex]\( e^{-x} = e^{2x + 6} \)[/tex], let’s go through the steps methodically:

1. Given Equation:
[tex]\[ e^{-x} = e^{2x + 6} \][/tex]

2. Since the bases of the exponents are the same (both [tex]\( e \)[/tex]), we can equate the exponents:
[tex]\[ -x = 2x + 6 \][/tex]

3. Move all the terms involving [tex]\( x \)[/tex] to one side:
[tex]\[ -x - 2x = 6 \][/tex]

4. Combine like terms:
[tex]\[ -3x = 6 \][/tex]

5. Solve for [tex]\( x \)[/tex]:
[tex]\[ x = \frac{6}{-3} \][/tex]

[tex]\[ x = -2 \][/tex]

6. Check the solution with the given options:
The given options are [tex]\( x = 2 \)[/tex], [tex]\( x = 4 \)[/tex], [tex]\( x = -4 \)[/tex], [tex]\( x = -2 \)[/tex].

The correct solution derived from the equation is [tex]\( x = -2 \)[/tex].

Therefore, the correct answer is:
[tex]\[ x = -2 \][/tex]