Answer :
Sure, let's calculate the molar masses of the given compounds using the periodic table to get their atomic masses. Here are the atomic masses we will use for the calculation:
- Sodium (Na): 22.99 g/mol
- Oxygen (O): 16.00 g/mol
- Hydrogen (H): 1.01 g/mol
- Carbon (C): 12.01 g/mol
- Sulfur (S): 32.07 g/mol
- Calcium (Ca): 40.08 g/mol
- Magnesium (Mg): 24.31 g/mol
- Phosphorus (P): 30.97 g/mol
Let's go through each compound one by one:
1. Sodium hydroxide (NaOH):
[tex]\[ \text{Molar mass of NaOH} = \text{Atomic mass of Na} + \text{Atomic mass of O} + \text{Atomic mass of H} \][/tex]
[tex]\[ = 22.99 + 16.00 + 1.01 = 40.00 \, g/mol \][/tex]
Therefore, the molar mass of NaOH is [tex]\( \boxed{40.00} \, g/mol \)[/tex].
2. Water (H[tex]\(_2\)[/tex]O):
[tex]\[ \text{Molar mass of H}_2\text{O} = 2 \times \text{Atomic mass of H} + \text{Atomic mass of O} \][/tex]
[tex]\[ = 2 \times 1.01 + 16.00 = 18.02 \, g/mol \][/tex]
Therefore, the molar mass of H[tex]\(_2\)[/tex]O is [tex]\( \boxed{18.02} \, g/mol \)[/tex].
3. Glucose (C[tex]\(_6\)[/tex]H[tex]\(_{12}\)[/tex]O[tex]\(_6\)[/tex]):
[tex]\[ \text{Molar mass of C}_6\text{H}_{12}\text{O}_6 = 6 \times \text{Atomic mass of C} + 12 \times \text{Atomic mass of H} + 6 \times \text{Atomic mass of O} \][/tex]
[tex]\[ = 6 \times 12.01 + 12 \times 1.01 + 6 \times 16.00 = 72.06 + 12.12 + 96.00 = 180.18 \, g/mol \][/tex]
Therefore, the molar mass of C[tex]\(_6\)[/tex]H[tex]\(_{12}\)[/tex]O[tex]\(_6\)[/tex] is [tex]\( \boxed{180.18} \, g/mol \)[/tex].
4. Calcium sulfate (CaSO[tex]\(_4\)[/tex]):
[tex]\[ \text{Molar mass of CaSO}_4 = \text{Atomic mass of Ca} + \text{Atomic mass of S} + 4 \times \text{Atomic mass of O} \][/tex]
[tex]\[ = 40.08 + 32.07 + 4 \times 16.00 = 40.08 + 32.07 + 64.00 = 136.15 \, g/mol \][/tex]
Therefore, the molar mass of CaSO[tex]\(_4\)[/tex] is [tex]\( \boxed{136.15} \, g/mol \)[/tex].
5. Magnesium phosphate (Mg[tex]\(_3\)[/tex](PO[tex]\(_4\)[/tex])[tex]\(_2\)[/tex]):
[tex]\[ \text{Molar mass of Mg}_3(\text{PO}_4)_2 = 3 \times \text{Atomic mass of Mg} + 2 \times (\text{Atomic mass of P} + 4 \times \text{Atomic mass of O}) \][/tex]
[tex]\[ = 3 \times 24.31 + 2 \times (30.97 + 4 \times 16.00) \][/tex]
[tex]\[ = 3 \times 24.31 + 2 \times (30.97 + 64.00) \][/tex]
[tex]\[ = 72.93 + 2 \times 94.97 \][/tex]
[tex]\[ = 72.93 + 189.94 = 262.87 \, g/mol \][/tex]
Therefore, the molar mass of Mg[tex]\(_3\)[/tex](PO[tex]\(_4\)[/tex])[tex]\(_2\)[/tex] is [tex]\( \boxed{262.87} \, g/mol \)[/tex].
To summarize:
- Sodium hydroxide (NaOH): [tex]\( \boxed{40.00} \, g/mol \)[/tex]
- Water (H[tex]\(_2\)[/tex]O): [tex]\( \boxed{18.02} \, g/mol \)[/tex]
- Glucose (C[tex]\(_6\)[/tex]H[tex]\(_{12}\)[/tex]O[tex]\(_6\)[/tex]): [tex]\( \boxed{180.18} \, g/mol \)[/tex]
- Calcium sulfate (CaSO[tex]\(_4\)[/tex]): [tex]\( \boxed{136.15} \, g/mol \)[/tex]
- Magnesium phosphate (Mg[tex]\(_3\)[/tex](PO[tex]\(_4\)[/tex])[tex]\(_2\)[/tex]): [tex]\( \boxed{262.87} \, g/mol \)[/tex]
- Sodium (Na): 22.99 g/mol
- Oxygen (O): 16.00 g/mol
- Hydrogen (H): 1.01 g/mol
- Carbon (C): 12.01 g/mol
- Sulfur (S): 32.07 g/mol
- Calcium (Ca): 40.08 g/mol
- Magnesium (Mg): 24.31 g/mol
- Phosphorus (P): 30.97 g/mol
Let's go through each compound one by one:
1. Sodium hydroxide (NaOH):
[tex]\[ \text{Molar mass of NaOH} = \text{Atomic mass of Na} + \text{Atomic mass of O} + \text{Atomic mass of H} \][/tex]
[tex]\[ = 22.99 + 16.00 + 1.01 = 40.00 \, g/mol \][/tex]
Therefore, the molar mass of NaOH is [tex]\( \boxed{40.00} \, g/mol \)[/tex].
2. Water (H[tex]\(_2\)[/tex]O):
[tex]\[ \text{Molar mass of H}_2\text{O} = 2 \times \text{Atomic mass of H} + \text{Atomic mass of O} \][/tex]
[tex]\[ = 2 \times 1.01 + 16.00 = 18.02 \, g/mol \][/tex]
Therefore, the molar mass of H[tex]\(_2\)[/tex]O is [tex]\( \boxed{18.02} \, g/mol \)[/tex].
3. Glucose (C[tex]\(_6\)[/tex]H[tex]\(_{12}\)[/tex]O[tex]\(_6\)[/tex]):
[tex]\[ \text{Molar mass of C}_6\text{H}_{12}\text{O}_6 = 6 \times \text{Atomic mass of C} + 12 \times \text{Atomic mass of H} + 6 \times \text{Atomic mass of O} \][/tex]
[tex]\[ = 6 \times 12.01 + 12 \times 1.01 + 6 \times 16.00 = 72.06 + 12.12 + 96.00 = 180.18 \, g/mol \][/tex]
Therefore, the molar mass of C[tex]\(_6\)[/tex]H[tex]\(_{12}\)[/tex]O[tex]\(_6\)[/tex] is [tex]\( \boxed{180.18} \, g/mol \)[/tex].
4. Calcium sulfate (CaSO[tex]\(_4\)[/tex]):
[tex]\[ \text{Molar mass of CaSO}_4 = \text{Atomic mass of Ca} + \text{Atomic mass of S} + 4 \times \text{Atomic mass of O} \][/tex]
[tex]\[ = 40.08 + 32.07 + 4 \times 16.00 = 40.08 + 32.07 + 64.00 = 136.15 \, g/mol \][/tex]
Therefore, the molar mass of CaSO[tex]\(_4\)[/tex] is [tex]\( \boxed{136.15} \, g/mol \)[/tex].
5. Magnesium phosphate (Mg[tex]\(_3\)[/tex](PO[tex]\(_4\)[/tex])[tex]\(_2\)[/tex]):
[tex]\[ \text{Molar mass of Mg}_3(\text{PO}_4)_2 = 3 \times \text{Atomic mass of Mg} + 2 \times (\text{Atomic mass of P} + 4 \times \text{Atomic mass of O}) \][/tex]
[tex]\[ = 3 \times 24.31 + 2 \times (30.97 + 4 \times 16.00) \][/tex]
[tex]\[ = 3 \times 24.31 + 2 \times (30.97 + 64.00) \][/tex]
[tex]\[ = 72.93 + 2 \times 94.97 \][/tex]
[tex]\[ = 72.93 + 189.94 = 262.87 \, g/mol \][/tex]
Therefore, the molar mass of Mg[tex]\(_3\)[/tex](PO[tex]\(_4\)[/tex])[tex]\(_2\)[/tex] is [tex]\( \boxed{262.87} \, g/mol \)[/tex].
To summarize:
- Sodium hydroxide (NaOH): [tex]\( \boxed{40.00} \, g/mol \)[/tex]
- Water (H[tex]\(_2\)[/tex]O): [tex]\( \boxed{18.02} \, g/mol \)[/tex]
- Glucose (C[tex]\(_6\)[/tex]H[tex]\(_{12}\)[/tex]O[tex]\(_6\)[/tex]): [tex]\( \boxed{180.18} \, g/mol \)[/tex]
- Calcium sulfate (CaSO[tex]\(_4\)[/tex]): [tex]\( \boxed{136.15} \, g/mol \)[/tex]
- Magnesium phosphate (Mg[tex]\(_3\)[/tex](PO[tex]\(_4\)[/tex])[tex]\(_2\)[/tex]): [tex]\( \boxed{262.87} \, g/mol \)[/tex]
