Use the following table to help you respond to the prompts below.

Codons Found in Messenger RNA

[tex]\[
\begin{array}{|c|c|c|c|c|c|}
\hline
\multicolumn{6}{|c|}{\text{Second Base}} \\
\hline
\text{First Base} & \text{U} & \text{C} & \text{A} & \text{G} & \text{Third Base} \\
\hline
\text{U} & \begin{tabular}{l}
\text{Phe} \\
\text{Phe} \\
\text{Leu} \\
\text{Leu}
\end{tabular} & \begin{tabular}{l}
\text{Ser} \\
\text{Ser} \\
\text{Ser} \\
\text{Ser}
\end{tabular} & \begin{tabular}{l}
\text{Tyr} \\
\text{Tyr} \\
\text{Stop} \\
\text{Stop}
\end{tabular} & \begin{tabular}{l}
\text{Cys} \\
\text{Cys} \\
\text{Stop} \\
\text{Trp}
\end{tabular} & \begin{tabular}{l}
\text{U} \\
\text{C} \\
\text{A} \\
\text{G}
\end{tabular} \\
\hline
\text{C} & \begin{tabular}{l}
\text{Leu} \\
\text{Leu} \\
\text{Leu} \\
\text{Leu}
\end{tabular} & \begin{tabular}{l}
\text{Pro} \\
\text{Pro} \\
\text{Pro} \\
\text{Pro}
\end{tabular} & \begin{tabular}{l}
\text{His} \\
\text{His} \\
\text{Gln} \\
\text{Gln}
\end{tabular} & \begin{tabular}{l}
\text{Arg} \\
\text{Arg} \\
\text{Arg} \\
\text{Arg}
\end{tabular} & \begin{tabular}{l}
\text{U} \\
\text{C} \\
\text{A} \\
\text{G}
\end{tabular} \\
\hline
\text{A} & \begin{tabular}{l}
\text{Ile} \\
\text{Ile} \\
\text{Ile} \\
\text{Met}
\end{tabular} & \begin{tabular}{l}
\text{Thr} \\
\text{Thr} \\
\text{Thr} \\
\text{Thr}
\end{tabular} & \begin{tabular}{l}
\text{Asn} \\
\text{Asn} \\
\text{Lys} \\
\text{Lys}
\end{tabular} & \begin{tabular}{l}
\text{Ser} \\
\text{Ser} \\
\text{Arg} \\
\text{Arg}
\end{tabular} & \begin{tabular}{l}
\text{U} \\
\text{C} \\
\text{A} \\
\text{G}
\end{tabular} \\
\hline
\text{G} & \begin{tabular}{l}
\text{Val} \\
\text{Val} \\
\text{Val} \\
\text{Val}
\end{tabular} & \begin{tabular}{l}
\text{Ala} \\
\text{Ala} \\
\text{Ala} \\
\text{Ala}
\end{tabular} & \begin{tabular}{l}
\text{Asp} \\
\text{Asp} \\
\text{Glu} \\
\text{Glu}
\end{tabular} & \begin{tabular}{l}
\text{Gly} \\
\text{Gly} \\
\text{Gly} \\
\text{Gly}
\end{tabular} & \begin{tabular}{l}
\text{U} \\
\text{C} \\
\text{A} \\
\text{G}
\end{tabular} \\
\hline
\end{array}
\][/tex]



Answer :

Let's address the primary problem step-by-step using thorough mathematical reasoning:

### Problem Statement

1. Olivia initially has [tex]$23. 2. She buys 5 bagels, each costing $[/tex]3.

### Solution

Step 1: Initial Money
- Olivia starts with [tex]$23. \[ \text{Initial Money} = \$[/tex]23 \]

Step 2: Cost per Bagel
- Each bagel costs [tex]$3. \[ \text{Cost per Bagel} = \$[/tex]3 \]

Step 3: Total Number of Bagels Purchased
- Olivia buys 5 bagels.

[tex]\[ \text{Number of Bagels} = 5 \][/tex]

Step 4: Total Money Spent on Bagels
- To find the total amount of money Olivia spends on bagels, multiply the number of bagels by the cost per bagel.

[tex]\[ \text{Total Money Spent} = \text{Number of Bagels} \times \text{Cost per Bagel} \][/tex]
[tex]\[ \text{Total Money Spent} = 5 \times 3 = \$15 \][/tex]

Step 5: Money Left After Purchase
- Subtract the total money spent on bagels from the initial amount of money Olivia has.

[tex]\[ \text{Money Left} = \text{Initial Money} - \text{Total Money Spent} \][/tex]
[tex]\[ \text{Money Left} = 23 - 15 = \$8 \][/tex]

### Final Answer
Based on the calculations:
- Total Money Spent on Bagels: [tex]$15 - Money Left After Purchase: $[/tex]8

These results can be confirmed as follows:
1. Olivia spends [tex]$15 in total on the bagels. 2. After the purchase, Olivia has $[/tex]8 remaining.

So, the amounts are [tex]$15 spent on bagels and $[/tex]8 left over.