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In pea plants, yellow seed color [tex]$(Y)$[/tex] is dominant and green seed color [tex]$(y)$[/tex] is recessive. Based on the Punnett squares, what are the chances that the offspring in the second generation will have green seeds?

\begin{tabular}{|c|c|c|}
\hline First Generation & [tex]$Y$[/tex] & [tex]$Y$[/tex] \\
\hline[tex]$y$[/tex] & [tex]$Y y$[/tex] & [tex]$Y y$[/tex] \\
\hline[tex]$y$[/tex] & [tex]$Y y$[/tex] & [tex]$Y y$[/tex] \\
\hline
\end{tabular}

\begin{tabular}{|c|c|c|}
\hline Second Generation & [tex]$Y$[/tex] & [tex]$y$[/tex] \\
\hline[tex]$Y$[/tex] & [tex]$Y Y$[/tex] & [tex]$Y y$[/tex] \\
\hline[tex]$y$[/tex] & [tex]$Y y$[/tex] & [tex]$y y$[/tex] \\
\hline
\end{tabular}

There is a [tex]$\square$[/tex] \% chance that the offspring will have green seeds.



Answer :

GinnyAnswer
To determine the probability that the offspring in the second generation will have green seeds, we need to analyze the possible genotype combinations.

From the second generation Punnett square, we have the following combinations:

[tex]\[ \begin{array}{|c|c|c|} \hline \ & Y & y \\ \hline Y & YY & Yy \\ \hline y & Yy & yy \\ \hline \end{array} \][/tex]

These combinations are:
1. YY
2. Yy
3. Yy
4. yy

Now we need to count the occurrences of each genotype. Specifically, we are interested in the genotype 'yy' because it results in green seeds.

- The 'yy' combination appears once.

Next, we calculate the total number of genotype combinations. There are 4 possible combinations in total.

To find the probability that the offspring will have green seeds, we use the formula:

[tex]\[ \text{Probability} = \left(\frac{\text{Number of 'yy' combinations}}{\text{Total number of combinations}}\right) \times 100 \][/tex]

Substituting the numbers we have:

[tex]\[ \text{Probability} = \left(\frac{1}{4}\right) \times 100 = 25.0\% \][/tex]

Therefore, there is a 25.0% chance that the offspring will have green seeds.

[tex]\[ \boxed{25.0} \][/tex]

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