The two-way table shows the number of sport utility vehicles with certain features for sale at the car lot.

\begin{tabular}{|c|c|c|c|}
\hline & \begin{tabular}{c}
4-Wheel \\
Drive
\end{tabular} & \begin{tabular}{c}
No 4-Wheel \\
Drive
\end{tabular} & Total \\
\hline Third-Row Seats & 18 & 12 & 30 \\
\hline No Third-Row Seats & 7 & 28 & 35 \\
\hline Total & 25 & 40 & 65 \\
\hline
\end{tabular}

What is the probability that a randomly selected car with no 4-wheel drive has third-row seats?

A. 0.3
B. 0.4
C. 0.7
D. 0.8



Answer :

To determine the probability that a randomly selected car with no 4-wheel drive has third-row seats, we need to consider the relevant entries from the two-way table provided.

Here are the steps to find the desired probability:

1. Identify the total number of cars with no 4-wheel drive:
According to the table, the total number of cars with no 4-wheel drive is [tex]\( 40 \)[/tex].

2. Identify the number of cars with no 4-wheel drive that have third-row seats:
The table shows that the number of cars with no 4-wheel drive and third-row seats is [tex]\( 12 \)[/tex].

3. Calculate the probability:
To find the probability that a randomly selected car with no 4-wheel drive has third-row seats, we divide the number of cars with no 4-wheel drive and third-row seats by the total number of cars with no 4-wheel drive.

[tex]\[ \text{Probability} = \frac{\text{Number of cars with no 4-wheel drive and third-row seats}}{\text{Total number of cars with no 4-wheel drive}} \][/tex]

Substituting the values from the table:

[tex]\[ \text{Probability} = \frac{12}{40} \][/tex]

4. Simplify the fraction:
Simplifying [tex]\(\frac{12}{40}\)[/tex] gives us:

[tex]\[ \frac{12}{40} = 0.3 \][/tex]

Therefore, the probability that a randomly selected car with no 4-wheel drive has third-row seats is [tex]\(0.3\)[/tex].

Given the multiple choices, the correct answer is:

0.3