Answered

What is the force exerted by an object with a mass of [tex][tex][tex]$1.00 \times 10^3$[/tex][/tex][/tex] kilograms and an acceleration of [tex]4.5 \, \text{meters/second}^2[/tex]?

A. [tex]0.9 \times 10^3[/tex] newtons
B. [tex]2.5 \times 10^3[/tex] newtons
C. [tex]4.5 \times 10^3[/tex] newtons
D. [tex]9.0 \times 10^3[/tex] newtons
E. [tex]9.6 \times 10^3[/tex] newtons



Answer :

Answer:

the force = C. 4.5 × 10³ Newtons

Step-by-step explanation:

We can find the force exerted by the object by using the Newton's second law:

[tex]\boxed{a=\frac{F}{m} }[/tex]

where:

  • [tex]a=\text{acceleration}[/tex]
  • [tex]F=\text{force}[/tex]
  • [tex]m=\text{mass}[/tex]

Given:

  • [tex]m=1.00\times10^3\ kg[/tex]
  • [tex]a=4.5\ m/s^2[/tex]

Then:

[tex]\displaystyle a=\frac{F}{m}[/tex]

[tex]\displaystyle 4.5=\frac{F}{1.00\times10^3}[/tex]

[tex]F=4.5\times1.00\times10^3[/tex]

[tex]F=\bf 4.5\times10^3\ N[/tex]