Answered

Insert either [tex]$\ \textless \ $[/tex] or [tex]$\ \textgreater \ $[/tex] to make the statement true:

[tex]\[ -\frac{5}{6} \quad-\frac{8}{9} \][/tex]

A. [tex]$\ \textless \ $[/tex]
B. [tex]$\ \textgreater \ $[/tex]



Answer :

To determine whether [tex]\(-\frac{5}{6}\)[/tex] is less than or greater than [tex]\(-\frac{8}{9}\)[/tex], consider the properties of negative fractions and how they compare to each other on the number line.

### Step-by-Step Solution:

1. Understand the Position on the Number Line:
When comparing two negative fractions, the fraction with the smaller absolute value (ignoring the negative sign) represents a number closer to zero and is therefore the greater of the two numbers. Conversely, the fraction with the larger absolute value represents a number farther from zero and thus is smaller when considering negative values.

2. Compare Absolute Values:
Let's compare the absolute values of the given fractions:
- The absolute value of [tex]\(-\frac{5}{6}\)[/tex] is [tex]\(\frac{5}{6}\)[/tex].
- The absolute value of [tex]\(-\frac{8}{9}\)[/tex] is [tex]\(\frac{8}{9}\)[/tex].

3. Find a Common Denominator:
To compare [tex]\(\frac{5}{6}\)[/tex] and [tex]\(\frac{8}{9}\)[/tex] directly, we can convert them to have a common denominator. The least common multiple (LCM) of 6 and 9 is 18.

- Converting [tex]\(\frac{5}{6}\)[/tex] to a denominator of 18:
[tex]\[ \frac{5}{6} = \frac{5 \times 3}{6 \times 3} = \frac{15}{18} \][/tex]

- Converting [tex]\(\frac{8}{9}\)[/tex] to a denominator of 18:
[tex]\[ \frac{8}{9} = \frac{8 \times 2}{9 \times 2} = \frac{16}{18} \][/tex]

4. Compare Converted Fractions:
Now that both fractions have the same denominator, we can compare the numerators:
[tex]\[ \frac{15}{18} \quad \text{and} \quad \frac{16}{18} \][/tex]

Since [tex]\(15 < 16\)[/tex], it implies:
[tex]\[ \frac{15}{18} < \frac{16}{18} \][/tex]

5. Interpret the Comparison for Negative Values:
Since [tex]\(\frac{5}{6} < \frac{8}{9}\)[/tex], the negative versions of these fractions will have the reverse inequality:
[tex]\[ -\frac{5}{6} > -\frac{8}{9} \][/tex]

Therefore, the correct symbol to insert in the statement [tex]\(-\frac{5}{6} \quad -\frac{8}{9}\)[/tex] is [tex]\(>\)[/tex]:
[tex]\[ -\frac{5}{6} > -\frac{8}{9} \][/tex]