Which system of equations can be used to find the roots of the equation [tex]\(12x^3 - 5x = 2x^2 + x + 6\)[/tex]?

A. [tex]\(\left\{\begin{array}{l} y = 12x^3 - 5x \\ y = 2x^2 + x + 6 \end{array}\right.\)[/tex]

B. [tex]\(\left\{\begin{array}{l} y = 12x^3 - 5x + 6 \\ y = 2x^2 + x \end{array}\right.\)[/tex]

C. [tex]\(\left\{\begin{array}{l} y = 12x^3 - 2x^2 - 6x \\ y = 6 \end{array}\right.\)[/tex]

D. [tex]\(\left\{\begin{array}{l} y = 12x^3 - 2x^2 - 6x - 6 \\ y = 0 \end{array}\right.\)[/tex]



Answer :

To find the roots of the given equation [tex]\( 12x^3 - 5x = 2x^2 + x + 6 \)[/tex], we first need to form an equation in standard polynomial form (i.e., set the equation to zero).

Step-by-Step Solution:

1. Rewrite the given equation:
[tex]\[ 12x^3 - 5x = 2x^2 + x + 6 \][/tex]

2. Move all terms to one side of the equation:
[tex]\[ 12x^3 - 5x - 2x^2 - x - 6 = 0 \][/tex]

3. Combine like terms:
[tex]\[ 12x^3 - 2x^2 - 6x - 6 = 0 \][/tex]

4. Represent this polynomial equation with [tex]\(y\)[/tex]:
[tex]\[ y = 12x^3 - 2x^2 - 6x - 6 \][/tex]
To find the roots, we need to set [tex]\( y = 0 \)[/tex].

Thus, the system of equations that can be used to find the roots is:
[tex]\[ \left\{\begin{array}{l} y = 12x^3 - 2x^2 - 6x - 6 \\ y = 0 \end{array}\right. \][/tex]

The correct answer is:
[tex]\[ \left\{\begin{array}{l} y = 12x^3 - 2x^2 - 6x - 6 \\ y = 0 \end{array}\right. \][/tex]