Instructions: Choose the best answer. If necessary, use the paper you were given.

Question:
At a supermarket, oranges cost [tex]\[tex]$1.30[/tex] per pound and pears cost [tex]\$[/tex]1.90[/tex] per pound. Misha spent less than [tex]\$10.00[/tex] on 2 pounds of oranges and [tex]x[/tex] pounds of pears. Which inequality represents this situation?

A. [tex]2(1.30) + 1.90x \ \textless \ 10.00[/tex]

B. [tex]2(1.90) + 1.30x \ \textless \ 10.00[/tex]

C. [tex]2(1.30 + 1.90)x \ \textless \ 10.00[/tex]

D. [tex]\left(\frac{1.30 + 1.90}{2}\right)x \ \textless \ 10.00[/tex]



Answer :

To solve this problem, we need to figure out how much Misha spends on oranges and pears and then represent that mathematically as an inequality.

1. Determine the cost of 2 pounds of oranges:
- Oranges cost \[tex]$1.30 per pound. - For 2 pounds, the cost of oranges would be \(2 \times 1.30\). \[ 2 \times 1.30 = 2.60 \] 2. Determine the total amount of money spent: - Misha spends less than \$[/tex]10.00 in total.

3. Determine the amount left for pears:
- Subtract the cost of the oranges from the total money spent.

[tex]\[ 10.00 - 2.60 = 7.40 \][/tex]

4. Determine the inequality for pears:
- Pears cost \$1.90 per pound.
- Let [tex]\(x\)[/tex] be the weight in pounds of pears.
- The cost of pears would be [tex]\(1.90x\)[/tex].
- This cost should be less than the remaining money:

[tex]\[ 1.90x < 7.40 \][/tex]

Therefore, the correct inequality that represents the situation is [tex]\(1.90x < 7.40\)[/tex]. Hence, the best answer among the provided choices is:

[tex]\[ 2(1.30) + 1.90x < 10.00 \][/tex]