Finding Possible Side Lengths of a Triangle

A triangle has side lengths measuring [tex]20 \, \text{cm}[/tex], [tex]5 \, \text{cm}[/tex], and [tex]n \, \text{cm}[/tex]. Which describes the possible values of [tex]n[/tex]?

A. [tex]5 \ \textless \ n \ \textless \ 15[/tex]
B. [tex]5 \ \textless \ n \ \textless \ 20[/tex]
C. [tex]15 \ \textless \ n \ \textless \ 20[/tex]
D. [tex]15 \ \textless \ n \ \textless \ 25[/tex]



Answer :

To determine the possible values of [tex]\( n \)[/tex] for the third side of a triangle given side lengths of [tex]\( 20 \)[/tex] cm and [tex]\( 5 \)[/tex] cm, we use the triangle inequality theorem. The theorem states:

1. The sum of the lengths of any two sides of a triangle must be greater than the length of the third side.
2. This requirement must be satisfied for all three combinations of the sides.

Given the sides [tex]\( a = 20 \)[/tex] cm, [tex]\( b = 5 \)[/tex] cm, and [tex]\( c = n \)[/tex] cm, we can derive the inequalities as follows:

1. [tex]\( a + b > c \)[/tex]
2. [tex]\( a + c > b \)[/tex]
3. [tex]\( b + c > a \)[/tex]

Substituting the given side lengths into the inequalities:

1. [tex]\( 20 + 5 > n \)[/tex]
[tex]\[ 25 > n \][/tex]
[tex]\[ n < 25 \][/tex]

2. [tex]\( 20 + n > 5 \)[/tex]
[tex]\[ n > -15 \][/tex]
Since [tex]\( n \)[/tex] must be a positive length, we disregard [tex]\( n > -15 \)[/tex] as it is always true for any positive number.

3. [tex]\( 5 + n > 20 \)[/tex]
[tex]\[ n > 15 \][/tex]

Combining these inequalities gives:
[tex]\[ 15 < n < 25 \][/tex]

Therefore, the correct range for the side length [tex]\( n \)[/tex] is [tex]\( 15 < n < 25 \)[/tex].

From the given multiple-choice options, the correct answer is:
[tex]\[ 15 < n < 25 \][/tex]