Answer :
Certainly! When sulfuric acid [tex]\((H_2SO_4)\)[/tex] reacts with dissolved sodium hydroxide [tex]\((NaOH)\)[/tex], the reaction produces sodium sulfate [tex]\((Na_2SO_4)\)[/tex] and water [tex]\((H_2O)\)[/tex].
To find the balanced chemical equation for this reaction, follow these steps:
1. Write down the reactants and the possible products:
[tex]\[ H_2SO_4 (aq) + NaOH (aq) \rightarrow Na_2SO_4 (aq) + H_2O (l) \][/tex]
2. Balance the sodium atoms:
Since there are two sodium atoms in [tex]\(Na_2SO_4\)[/tex], we need two [tex]\(NaOH\)[/tex] molecules.
[tex]\[ H_2SO_4 (aq) + 2 NaOH (aq) \rightarrow Na_2SO_4 (aq) + H_2O (l) \][/tex]
3. Balance the hydrogen atoms:
Each [tex]\(NaOH\)[/tex] provides one hydrogen atom and one hydroxide ion ([tex]\(OH^-\)[/tex]). Two [tex]\(NaOH\)[/tex] molecules will provide two hydrogen atoms in total. Combined with the two hydrogen atoms from [tex]\(H_2SO_4\)[/tex], we have four hydrogen atoms to form two water molecules:
[tex]\[ H_2SO_4 (aq) + 2 NaOH (aq) \rightarrow Na_2SO_4 (aq) + 2 H_2O (l) \][/tex]
4. Balance the oxygen atoms:
Each [tex]\(NaOH\)[/tex] provides one [tex]\(OH^-\)[/tex], leading to two [tex]\(OH^-\)[/tex] ions available to bond with the hydrogen atoms to form water, matching the products' two water molecules contribution.
Thus, the correctly balanced chemical equation for this reaction is:
[tex]\[ H_2SO_4 (aq) + 2 NaOH (aq) \rightarrow Na_2SO_4 (aq) + 2 H_2O (l) \][/tex]
This equation shows that one molecule of sulfuric acid reacts with two molecules of sodium hydroxide to produce one molecule of sodium sulfate and two molecules of water.
To find the balanced chemical equation for this reaction, follow these steps:
1. Write down the reactants and the possible products:
[tex]\[ H_2SO_4 (aq) + NaOH (aq) \rightarrow Na_2SO_4 (aq) + H_2O (l) \][/tex]
2. Balance the sodium atoms:
Since there are two sodium atoms in [tex]\(Na_2SO_4\)[/tex], we need two [tex]\(NaOH\)[/tex] molecules.
[tex]\[ H_2SO_4 (aq) + 2 NaOH (aq) \rightarrow Na_2SO_4 (aq) + H_2O (l) \][/tex]
3. Balance the hydrogen atoms:
Each [tex]\(NaOH\)[/tex] provides one hydrogen atom and one hydroxide ion ([tex]\(OH^-\)[/tex]). Two [tex]\(NaOH\)[/tex] molecules will provide two hydrogen atoms in total. Combined with the two hydrogen atoms from [tex]\(H_2SO_4\)[/tex], we have four hydrogen atoms to form two water molecules:
[tex]\[ H_2SO_4 (aq) + 2 NaOH (aq) \rightarrow Na_2SO_4 (aq) + 2 H_2O (l) \][/tex]
4. Balance the oxygen atoms:
Each [tex]\(NaOH\)[/tex] provides one [tex]\(OH^-\)[/tex], leading to two [tex]\(OH^-\)[/tex] ions available to bond with the hydrogen atoms to form water, matching the products' two water molecules contribution.
Thus, the correctly balanced chemical equation for this reaction is:
[tex]\[ H_2SO_4 (aq) + 2 NaOH (aq) \rightarrow Na_2SO_4 (aq) + 2 H_2O (l) \][/tex]
This equation shows that one molecule of sulfuric acid reacts with two molecules of sodium hydroxide to produce one molecule of sodium sulfate and two molecules of water.