The pair of points [tex]\((6, y)\)[/tex] and [tex]\((10, -1)\)[/tex] lie on a line with slope [tex]\(\frac{1}{4}\)[/tex]. What is the value of [tex]\(y\)[/tex]?

A. [tex]\(-5\)[/tex]
B. [tex]\(-2\)[/tex]
C. 2
D. 5



Answer :

To find the value of [tex]\( y \)[/tex] for the point [tex]\((6, y)\)[/tex] that lies on the same line as the point [tex]\((10, -1)\)[/tex] with a given slope of [tex]\(\frac{1}{4}\)[/tex]:

1. Identify the coordinates and slope:
- First point: [tex]\((10, -1)\)[/tex]
- Second point: [tex]\((6, y)\)[/tex]
- Slope, [tex]\( m = \frac{1}{4} \)[/tex]

2. Use the slope formula:
The slope [tex]\(m\)[/tex] between two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] is given by:
[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]

3. Substitute the known values:
Here, [tex]\( (x_1, y_1) = (10, -1) \)[/tex] and [tex]\( (x_2, y_2) = (6, y) \)[/tex]. Substituting these values into the slope formula, we get:
[tex]\[ \frac{1}{4} = \frac{y - (-1)}{6 - 10} \][/tex]

4. Simplify the denominator:
Since [tex]\( 6 - 10 = -4 \)[/tex], the equation becomes:
[tex]\[ \frac{1}{4} = \frac{y + 1}{-4} \][/tex]

5. Cross-multiply to solve for [tex]\( y \)[/tex]:
Cross-multiplying the terms gives:
[tex]\[ 1 \cdot (-4) = 4 \cdot (y + 1) \][/tex]
Simplifying this, we get:
[tex]\[ -4 = 4(y + 1) \][/tex]

6. Solve for [tex]\( y \)[/tex]:
Divide both sides by 4:
[tex]\[ -1 = y + 1 \][/tex]
Subtract 1 from both sides to isolate [tex]\( y \)[/tex]:
[tex]\[ y = -2 \][/tex]

So, the value of [tex]\( y \)[/tex] is:
[tex]\[ -2 \][/tex]

Thus, the correct answer is:
[tex]\[ \boxed{-2} \][/tex]