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Question 7 of 14

A family has seven children. If this family has exactly one boy, how many different birth and gender orders are possible?

There are __________ different birth and gender orders possible. (Type a whole number.)



Answer :

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Final answer:

There are 5040 different birth and gender orders possible with 7 children and exactly one boy in the family.


Explanation:

There are 7 children in the family with exactly one boy.

To calculate the different birth and gender orders, we use the concept of permutations. With 7 children and 1 boy, there are 7 spots to place the boy. The number of ways to arrange the rest of the children (girls) in the remaining spots is 6! (6 factorial).

Therefore, the total number of different birth and gender orders possible is 7 * 6! = 5040.


Learn more about Permutations and Combinations here:

https://brainly.com/question/34452834


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