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A body travels from [tex]\( A \)[/tex] to [tex]\( B \)[/tex] at [tex]\( 25 \, \text{m/s} \)[/tex] and from [tex]\( B \)[/tex] to [tex]\( A \)[/tex] at [tex]\( 50 \, \text{m/s} \)[/tex]. What is its average speed?

A. [tex]\( 0 \, \text{m/s} \)[/tex]
B. [tex]\( 16.3 \, \text{m/s} \)[/tex]
C. [tex]\( 37.5 \, \text{m/s} \)[/tex]
D. [tex]\( 33.3 \, \text{m/s} \)[/tex]



Answer :

GinnyAnswer
To determine the average speed of a body traveling from point A to point B and then returning from point B to point A, we can follow these steps:

1. Determine the speeds:
- Speed from A to B: [tex]\(25 \text{ m/s}\)[/tex]
- Speed from B to A: [tex]\(50 \text{ m/s}\)[/tex]

2. Assume the distance between A and B:
Let's assume the distance [tex]\(d\)[/tex] is 1 meter (or any other unit, but we'll use 1 meter here for simplicity).

3. Calculate the time taken for each leg of the journey:
- Time taken to travel from A to B:
[tex]\[ \text{Time}_{\text{A to B}} = \frac{d}{\text{Speed}_{\text{A to B}}} = \frac{1 \text{ m}}{25 \text{ m/s}} = 0.04 \text{ s} \][/tex]
- Time taken to travel from B to A:
[tex]\[ \text{Time}_{\text{B to A}} = \frac{d}{\text{Speed}_{\text{B to A}}} = \frac{1 \text{ m}}{50 \text{ m/s}} = 0.02 \text{ s} \][/tex]

4. Calculate the total distance traveled:
- Distance from A to B and back to A:
[tex]\[ \text{Total distance} = d + d = 1 \text{ m} + 1 \text{ m} = 2 \text{ m} \][/tex]

5. Calculate the total time taken:
- Total time for the journey from A to B and back to A:
[tex]\[ \text{Total time} = \text{Time}_{\text{A to B}} + \text{Time}_{\text{B to A}} = 0.04 \text{ s} + 0.02 \text{ s} = 0.06 \text{ s} \][/tex]

6. Calculate the average speed:
- Average speed is given by the formula:
[tex]\[ \text{Average speed} = \frac{\text{Total distance}}{\text{Total time}} = \frac{2 \text{ m}}{0.06 \text{ s}} = 33.33 \text{ m/s} \][/tex]

Comparing the given options, the correct answer is:
(d) [tex]\(33.3 \text{ m/s}\)[/tex]

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