Answered

A cable is 100 m long, has a cross-sectional area of 1.0 mm², and is made of a material with a Young's modulus of 1.0×10¹¹ N/m². If a 1000 N force is applied to stretch the cable, how far does it stretch?



Answer :

Answer:

0.1m

Explanation:

stretch =force ×original lenght/ young modulus ×cross sectional

=1000×100/1.0×10^11×1^-6m^2

stretch=0.1m or 10cm