Answer:
c. 1.79
Step-by-step explanation:
When changing the base of a logarithm so that it maintains its value, this formula can be applied:
[tex]log_b(a)=\dfrac{log_d(a)}{log_d(b)}[/tex],
where [tex]b\neq d[/tex].
[tex]\dotfill[/tex]
In this problem, b = 4, a = 12 and d = e (natural constant).
All we have to do is plug it in and evaluate its numerical value.
[tex]\dfrac{log_e(12)}{log_e(4)} =1.79[/tex]
We can verify by evaluating the value of the original logarithm,
[tex]log_4(12)=1.79[/tex].
Since they're the same, 1.79 is our final answer.