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1.1 The following payslip shows what Lorna earned for the month of May 2021.

\begin{tabular}{|c|c|c|c|}
\hline \multicolumn{4}{|c|}{ SISOKOLA SONKE'S FINANCIAL SERVICES } \\
\hline \multicolumn{4}{|c|}{\begin{tabular}{l}
Identity Number: 98020364351988 \\
Banking Details: Success Bank, Savings Account: 233556677
\end{tabular}} \\
\hline \multicolumn{4}{|c|}{ Payment Period: [tex]$01 / 05 / 2021$[/tex] to [tex]$31 / 05 / 2021$[/tex]} \\
\hline Basic Salary & R21 500 & Deductions & \\
\hline Performance Bonus & R 3025 & \begin{tabular}{l}
PAYE \\
UIF \\
Medical Aid \\
Total Deductions
\end{tabular} & \begin{tabular}{l}
R3 870 \\
(a) \\
R1 613 \\
(b)
\end{tabular} \\
\hline \begin{tabular}{l}
Gross Salary \\
Net Salary
\end{tabular} & \begin{tabular}{l}
R24 525 \\
(c)
\end{tabular} & & \\
\hline
\end{tabular}

1.1.1 Who is Lorna's employer? (1)

1.1.2 What is Lorna's Identity number? (1)

1.1.3 Determine the value of (a) if UIF is calculated at [tex]$1 \%$[/tex] of the gross earnings. Show your calculations.



Answer :

GinnyAnswer
Let's address each part of the question step by step.

1.1.1 Who is Lorna's employer?
- Lorna's employer is "SISOKOLA SONKE'S FINANCIAL SERVICES".

1.1.2 What is Lorna's Identity number?
- Lorna's Identity number is 98020364351988.

1.1.3 Determine the value of (a) if UIF is calculated at 1% of the gross earnings. Show your calculations.
- Step-by-Step Solution:
- First, recognize that UIF (Unemployment Insurance Fund) is 1% of Lorna's gross earnings.
- Lorna's gross earnings for May 2021 is R24 525.
- To find the UIF contribution, we calculate 1% of R24 525.
- This can be expressed as:
[tex]\[ \text{UIF} = \frac{1}{100} \times \text{Gross Earnings} \][/tex]
- Substituting the gross earnings value:
[tex]\[ \text{UIF} = \frac{1}{100} \times 24{,}525 \][/tex]
- This simplifies to:
[tex]\[ \text{UIF} = 245.25 \][/tex]

Therefore, the value of (a) is R245.25.