Certainly! Let's go through the question step by step.
### Question:
Which of the following alkenes will give a meso-product with Baeyer's reagent?
(A) 1-Butene
(B) Propene
(C) Cis-2-Butene
(D) Trans-2-Butene
### Explanation:
1. Baeyer's Reagent:
Baeyer's reagent is an aqueous solution of potassium permanganate (KMnO4). It is commonly used to test for the presence of double bonds (alkenes) and triple bonds (alkynes) in organic compounds. It reacts with alkenes to form diols (glycols).
2. Meso Compound:
A meso compound is a molecule with multiple stereocenters that is superimposable on its mirror image, meaning it has a plane of symmetry. For a product to be a meso compound, it must contain two identical chiral centers that are mirror images of each other.
3. Analyzing Each Option:
- (A) 1-Butene:
1-Butene has a double bond between the first and second carbon atoms. When it reacts with Baeyer's reagent, it forms a glycol. However, the product does not have the symmetry required to be a meso compound.
- (B) Propene:
Propene has a double bond between the first and second carbon atoms, similar to 1-butene, but with a shorter chain. The dihydroxylation product will also not be a meso compound.
- (C) Cis-2-Butene:
Cis-2-butene has a double bond between the second and third carbon atoms, with the two methyl groups on the same side of the double bond. When it reacts with Baeyer's reagent, it forms a glycol with hydroxyl groups on the same side of the molecule. This product has two chiral centers which are mirror images of each other, creating a plane of symmetry, making it a meso compound.
- (D) Trans-2-Butene:
Trans-2-butene has the two methyl groups on opposite sides of the double bond. The reaction with Baeyer's reagent will produce a glycol where the hydroxyl groups are on opposite sides, lacking the symmetry required for a meso compound.
### Conclusion:
Based on the analysis, Cis-2-Butene (C) is the only alkene among the options that will yield a meso-product when reacted with Baeyer's reagent.
Therefore, the correct answer is:
(C) Cis-2-Butene
