To determine which equations have no real solutions but have two complex solutions, we need to analyze the discriminant of each quadratic equation. For a quadratic equation in the standard form [tex]\( ax^2 + bx + c = 0 \)[/tex], the discriminant is given by [tex]\( \Delta = b^2 - 4ac \)[/tex].
If the discriminant is less than 0 ([tex]\( \Delta < 0 \)[/tex]), the quadratic equation has two complex solutions.
Let's analyze each given equation:
1. [tex]\( 3x^2 - 5x = -8 \)[/tex]
[tex]\[
\Rightarrow 3x^2 - 5x + 8 = 0
\][/tex]
The discriminant is:
[tex]\[
\Delta = (-5)^2 - 4 \cdot 3 \cdot 8 = 25 - 96 = -71
\][/tex]
Since the discriminant is less than 0, this equation has two complex solutions.
2. [tex]\( 2x^2 = 6x - 5 \)[/tex]
[tex]\[
\Rightarrow 2x^2 - 6x + 5 = 0
\][/tex]
The discriminant is:
[tex]\[
\Delta = (-6)^2 - 4 \cdot 2 \cdot 5 = 36 - 40 = -4
\][/tex]
Since the discriminant is less than 0, this equation also has two complex solutions.
3. [tex]\( 12x = 9x^2 + 4 \)[/tex]
[tex]\[
\Rightarrow 9x^2 - 12x + 4 = 0
\][/tex]
The discriminant is:
[tex]\[
\Delta = (-12)^2 - 4 \cdot 9 \cdot 4 = 144 - 144 = 0
\][/tex]
Since the discriminant is equal to 0, this equation has a double root (one real solution) and not complex solutions.
4. [tex]\( -x^2 - 10x = 34 \)[/tex]
[tex]\[
\Rightarrow -x^2 - 10x - 34 = 0
\][/tex]
The discriminant is:
[tex]\[
\Delta = (-10)^2 - 4 \cdot (-1) \cdot (-34) = 100 - 136 = -36
\][/tex]
Since the discriminant is less than 0, this equation has two complex solutions.
Therefore, the equations that have no real solutions but have two complex solutions are:
[tex]\[
\begin{array}{|c|c|}
\hline
3x^2 - 5x = -8 & 2x^2 = 6x - 5 \\
\hline
-x^2 - 10x = 34 &
\hline
\end{array}
\][/tex]
