The table shows the temperature at [tex]$08:00$[/tex] on the specified dates.

\begin{tabular}{|c|c|c|c|}
\hline Date & 1 January & 8 January & 15 January \\
\hline Temperature & [tex]$+1^{\circ} C$[/tex] & [tex]$-4^{\circ} C$[/tex] & [tex]$-3^{\circ} C$[/tex] \\
\hline
\end{tabular}

a. What is the difference between the temperatures on 1 January and 8 January?
[tex]$
\begin{array}{l}
+1^{\circ} C - (-4^{\circ} C) = +1^{\circ} C + 4^{\circ} C = 5^{\circ} C \\
\end{array}
$[/tex]

b. On 22 January, the temperature is [tex]$5^{\circ} C$[/tex] lower than on 15 January. What is the temperature on 22 January?
[tex]$
\begin{array}{l}
-3^{\circ} C - 5^{\circ} C = -8^{\circ} C \\
\end{array}
$[/tex]



Answer :

Certainly! Let's go through each part of the problem step-by-step.

### Part (a)
We need to determine the difference in temperature between 1 January and 8 January.

- The temperature on 1 January is [tex]\( +1^{\circ} \text{C} \)[/tex]
- The temperature on 8 January is [tex]\( -4^{\circ} \text{C} \)[/tex]

To find the difference between these temperatures, we subtract the temperature on 8 January from the temperature on 1 January:

[tex]\[ \text{Difference} = (+1^{\circ} \text{C}) - (-4^{\circ} \text{C}) \][/tex]

When subtracting a negative number, it is equivalent to adding the absolute value of that number:

[tex]\[ (+1^{\circ} \text{C}) - (-4^{\circ} \text{C}) = +1^{\circ} \text{C} + 4^{\circ} \text{C} = +5^{\circ} \text{C} \][/tex]

So, the difference in temperature between 1 January and 8 January is [tex]\( +5^{\circ} \text{C} \)[/tex].

### Part (b)
We need to find the temperature on 22 January, given that it is [tex]\( 5^{\circ} \text{C} \)[/tex] lower than the temperature on 15 January.

- The temperature on 15 January is [tex]\( -3^{\circ} \text{C} \)[/tex]

To find the temperature on 22 January, we subtract [tex]\( 5^{\circ} \text{C} \)[/tex] from the temperature on 15 January:

[tex]\[ \text{Temperature on 22 January} = (-3^{\circ} \text{C}) - (5^{\circ} \text{C}) \][/tex]

Performing the subtraction:

[tex]\[ -3^{\circ} \text{C} - 5^{\circ} \text{C} = -8^{\circ} \text{C} \][/tex]

So, the temperature on 22 January is [tex]\( -8^{\circ} \text{C} \)[/tex].