Simplify the expression:

[tex]\[ \frac{16^{\frac{5}{4}} \cdot 16^{\frac{1}{4}}}{\left(16^{\frac{1}{2}}\right)^2} = \][/tex]



Answer :

Sure, let's solve the given expression:

[tex]\[ \frac{16^{\frac{5}{4}} \cdot 16^{\frac{1}{4}}}{\left(16^{\frac{1}{2}}\right)^2} \][/tex]

First, recall the properties of exponents. When you multiply powers with the same base, you add the exponents:

[tex]\[ 16^{\frac{5}{4}} \cdot 16^{\frac{1}{4}} = 16^{\left(\frac{5}{4} + \frac{1}{4}\right)} \][/tex]

Let's add the exponents in the numerator:

[tex]\[ \frac{5}{4} + \frac{1}{4} = \frac{6}{4} = \frac{3}{2} \][/tex]

So, the expression in the numerator simplifies to:

[tex]\[ 16^{\frac{3}{2}} \][/tex]

Next, let's simplify the denominator. Recall the property of exponents: [tex]\((a^m)^n = a^{m \cdot n}\)[/tex]:

[tex]\[ \left(16^{\frac{1}{2}}\right)^2 = 16^{\left(\frac{1}{2} \cdot 2\right)} = 16^1 = 16 \][/tex]

Thus, the original expression now looks like:

[tex]\[ \frac{16^{\frac{3}{2}}}{16} \][/tex]

Now, use the property of exponents for division, where you subtract the exponents:

[tex]\[ \frac{16^{\frac{3}{2}}}{16^1} = 16^{\left(\frac{3}{2} - 1\right)} \][/tex]

Subtract the exponents:

[tex]\[ \frac{3}{2} - 1 = \frac{3}{2} - \frac{2}{2} = \frac{1}{2} \][/tex]

So, the expression simplifies to:

[tex]\[ 16^{\frac{1}{2}} \][/tex]

Finally, recall that raising a number to the [tex]\(\frac{1}{2}\)[/tex] power is the same as taking the square root:

[tex]\[ 16^{\frac{1}{2}} = \sqrt{16} = 4 \][/tex]

Hence, the result of the given expression is:

[tex]\[ 4.0 \][/tex]