To find the probability that a child spends less than 1 hour per day on electronics given that they spend at least 1 hour per day outside, we can follow these steps:
1. Identify the total number of children who spend at least 1 hour per day outside.
- From the table, we see that there are 16 children who spend at least 1 hour per day outside.
2. Identify the number of children who spend less than 1 hour per day on electronics and also spend at least 1 hour per day outside.
- From the table, there are 14 children who meet this criterion.
3. Calculate the probability.
- The probability is the ratio of the number of children who spend less than 1 hour per day on electronics (and at least 1 hour per day outside) to the total number of children who spend at least 1 hour per day outside.
[tex]\[
\text{Probability} = \frac{\text{Number of children who spend less than 1 hour per day on electronics and at least 1 hour per day outside}}{\text{Total number of children who spend at least 1 hour per day outside}}
\][/tex]
Which translates to:
[tex]\[
\text{Probability} = \frac{14}{16}
\][/tex]
4. Simplify the fraction and round to the nearest hundredth if necessary.
- Simplifying [tex]\(\frac{14}{16}\)[/tex] gives [tex]\(\frac{7}{8}\)[/tex].
- Converting [tex]\(\frac{7}{8}\)[/tex] to a decimal gives [tex]\(0.875\)[/tex].
- Rounding [tex]\(0.875\)[/tex] to the nearest hundredth gives [tex]\(0.88\)[/tex].
Thus, the probability that a child who spends at least 1 hour per day outside also spends less than 1 hour per day on electronics is [tex]\(0.88\)[/tex].
So the correct answer is [tex]\(0.88\)[/tex].
