Answered

Match the polynomial on the left with the appropriately factored expression on the right.

[tex]\[
\begin{array}{l}
8x^3 + 27 \\
8x^3 - 27
\end{array}
\][/tex]

[tex]\[
\begin{array}{l}
(2x - 3)\left(4x^2 + 6x + 9\right) \\
(2x + 3)\left(4x^2 + 6x + 9\right) \\
(2x + 3)\left(4x^2 - 6x + 9\right) \\
(2x - 3)\left(4x^2 - 6x + 9\right)
\end{array}
\][/tex]

Drag and drop each polynomial to its corresponding factored form.



Answer :

To match each polynomial with its appropriately factored expression, we will analyze and detail each polynomial factorization one by one.

### Step-by-Step Factorization Analysis:

#### 1. Factorizing [tex]\(8x^3 + 27\)[/tex]:

Given polynomial: [tex]\(8x^3 + 27\)[/tex]

This polynomial is a sum of cubes. The standard formula for a sum of cubes [tex]\(a^3 + b^3\)[/tex] is:
[tex]\[ a^3 + b^3 = (a + b)(a^2 - ab + b^2) \][/tex]

Here, [tex]\(a = 2x\)[/tex] and [tex]\(b = 3\)[/tex].

Applying the sum of cubes formula, we get:
[tex]\[ (2x)^3 + 3^3 = (2x + 3)((2x)^2 - 2x \cdot 3 + 3^2) \][/tex]

Simplifying the parts inside the parentheses:
[tex]\[ (2x + 3)(4x^2 - 6x + 9) \][/tex]

So, the factored form of [tex]\(8x^3 + 27\)[/tex] is:
[tex]\[ (2x + 3)(4x^2 - 6x + 9) \][/tex]

#### 2. Factorizing [tex]\(8x^3 - 27\)[/tex]:

Given polynomial: [tex]\(8x^3 - 27\)[/tex]

This polynomial is a difference of cubes. The standard formula for a difference of cubes [tex]\(a^3 - b^3\)[/tex] is:
[tex]\[ a^3 - b^3 = (a - b)(a^2 + ab + b^2) \][/tex]

Here, [tex]\(a = 2x\)[/tex] and [tex]\(b = 3\)[/tex].

Applying the difference of cubes formula, we get:
[tex]\[ (2x)^3 - 3^3 = (2x - 3)((2x)^2 + 2x \cdot 3 + 3^2) \][/tex]

Simplifying the parts inside the parentheses:
[tex]\[ (2x - 3)(4x^2 + 6x + 9) \][/tex]

So, the factored form of [tex]\(8x^3 - 27\)[/tex] is:
[tex]\[ (2x - 3)(4x^2 + 6x + 9) \][/tex]

### Matching the Polynomials with Their Factored Forms:

- [tex]\(8x^3 + 27\)[/tex] matches with [tex]\((2x + 3)(4x^2 - 6x + 9)\)[/tex]
- [tex]\(8x^3 - 27\)[/tex] matches with [tex]\((2x - 3)(4x^2 + 6x + 9)\)[/tex]

In summary:

- [tex]\(8 x^3 + 27\)[/tex] → [tex]\((2 x + 3)(4 x^2 - 6 x + 9)\)[/tex]
- [tex]\(8 x^3 - 27\)[/tex] → [tex]\((2 x - 3)(4 x^2 + 6 x + 9)\)[/tex]

These are the correct factorizations for each polynomial.