Final answer:
The work done when moving a block 3 m with a force of 25 N on a horizontal surface is 75 Joules.
Explanation:
Work done is calculated by multiplying the force applied by the displacement and the cos of the angle between the force and displacement. In this case, work = force x displacement x cos(angle).
Given force of 25 N, displacement of 3 m, and angle of 0°, work = 25 N x 3 m x cos(0°) = 75 Joules.
Therefore, the work done when moving a block 3 m with a force of 25 N on a horizontal surface is 75 Joules.
Learn more about work calculation in physics here:
https://brainly.com/question/33726554
