Type the correct answer in the box.

What's the kinetic energy of the object? Use [tex]KE = \frac{1}{2} mv^2[/tex].

Erica is competing in the shot put event at a track meet. She hurls a shot with a mass of 4 kilograms at a speed of 9 meters/second. The shot's kinetic energy is [tex]\square[/tex] joules.



Answer :

To find the kinetic energy of the shot, you can use the kinetic energy formula:

[tex]\[ KE = \frac{1}{2} mv^2 \][/tex]

where:
- [tex]\( m \)[/tex] is the mass of the shot,
- [tex]\( v \)[/tex] is the speed at which it is hurled.

Given:
- [tex]\( m = 4 \)[/tex] kilograms,
- [tex]\( v = 9 \)[/tex] meters/second,

you can plug these values into the formula.

First, calculate the velocity squared:

[tex]\[ v^2 = 9^2 = 81 \][/tex]

Next, multiply the mass by the squared velocity:

[tex]\[ m \cdot v^2 = 4 \cdot 81 = 324 \][/tex]

Finally, multiply by [tex]\( \frac{1}{2} \)[/tex]:

[tex]\[ KE = \frac{1}{2} \cdot 324 = 162 \][/tex]

Thus, the kinetic energy of the shot is [tex]\( 162 \)[/tex] joules.