You deposit [tex][tex]$\$[/tex] 4500[tex]$[/tex] in an account that earns [tex]$[/tex]2 \%[tex]$[/tex] per year simple interest. The equation that represents this situation is:

\[ A(n) = 4500 + (n-1)(0.02 \cdot 4500) \]

How much will you have in the account at the beginning of the 7th year? Round your answer to the nearest dollar.

A. [tex]$[/tex]\[tex]$ 5040$[/tex][/tex]
B. [tex][tex]$\$[/tex] 5130[tex]$[/tex]
C. [tex]$[/tex]\[tex]$ 4590$[/tex][/tex]
D. [tex][tex]$\$[/tex] 9900$[/tex]



Answer :

To determine how much you will have in the account at the beginning of the 7th year with a simple interest rate of [tex]\(2\%\)[/tex] per year, we can follow these steps:

1. Identify the variables in the given formula:
- Principal ([tex]\(P\)[/tex]): \[tex]$4500 (initial deposit) - Annual interest rate (\(r\)): 0.02 (2%) - Number of years (\(n\)): 7 2. Insert these values into the equation: \[ A(n) = 4500 + (n-1)(0.02 \cdot 4500) \] 3. Substitute \(n\) with 7: \[ A(7) = 4500 + (7-1)(0.02 \cdot 4500) \] 4. Simplify inside the parentheses: \[ A(7) = 4500 + 6(0.02 \cdot 4500) \] 5. Calculate the interest amount for one year: \[ 0.02 \cdot 4500 = 90 \] 6. Multiply this interest amount by the number of years minus one (since interest compounds on the initial amount): \[ 6 \cdot 90 = 540 \] 7. Add the interest obtained over 6 years to the principal amount: \[ A(7) = 4500 + 540 = 5040 \] 8. Round the result to the nearest dollar if necessary (in this case, it remains the same): \[ A(7) = 5040 \] Therefore, at the beginning of the 7th year, you will have \$[/tex]5040 in the account.

So, the correct answer is A. \$5040.