Answer :
To find the product of the denominator when multiplying across the unit conversion table, we need to handle the denominator's components separately.
Here's a detailed, step-by-step solution for this problem:
Given:
- [tex]\(moles\_ C _2 H _6\_initial = 24\)[/tex]
- [tex]\(moles\_ O _2\_needed = 7\)[/tex]
- [tex]\(moles\_ C _2 H _6\_reacting = 2\)[/tex]
We are dealing with the denominator here, so we specifically focus on multiplying the components in the denominator:
The denominator components are:
- [tex]\(moles\_ O _2\_needed = 7\)[/tex]
- [tex]\(moles\_ C _2 H _6\_reacting = 2\)[/tex]
To find the product of the denominator, multiply these components:
[tex]\[ 7 \text{ moles } O_2 \times 2 \text{ moles } C_2H_6 \][/tex]
Calculating this:
[tex]\[ 7 \times 2 = 14 \][/tex]
Thus, the product of the denominator is [tex]\(\boxed{14}\)[/tex].
Here's a detailed, step-by-step solution for this problem:
Given:
- [tex]\(moles\_ C _2 H _6\_initial = 24\)[/tex]
- [tex]\(moles\_ O _2\_needed = 7\)[/tex]
- [tex]\(moles\_ C _2 H _6\_reacting = 2\)[/tex]
We are dealing with the denominator here, so we specifically focus on multiplying the components in the denominator:
The denominator components are:
- [tex]\(moles\_ O _2\_needed = 7\)[/tex]
- [tex]\(moles\_ C _2 H _6\_reacting = 2\)[/tex]
To find the product of the denominator, multiply these components:
[tex]\[ 7 \text{ moles } O_2 \times 2 \text{ moles } C_2H_6 \][/tex]
Calculating this:
[tex]\[ 7 \times 2 = 14 \][/tex]
Thus, the product of the denominator is [tex]\(\boxed{14}\)[/tex].