A student was comparing the solubility of equal amounts of table salt and table sugar at different temperatures. The table below shows the four samples that the student used and the temperature of the water they were dissolved in.

\begin{tabular}{|c|c|c|c|}
\hline
Sample & Name & Chemical formula & Temperature of water [tex]$\left(^{\circ} C\right)$[/tex] \\
\hline
1 & Table sugar & [tex]$C_{12}H_{22}O_{11}$[/tex] & 80 \\
\hline
2 & Table sugar & [tex]$C_{12}H_{22}O_{11}$[/tex] & 45 \\
\hline
3 & Table salt & [tex]$NaCl$[/tex] & 55 \\
\hline
4 & Table salt & [tex]$NaCl$[/tex] & 63 \\
\hline
\end{tabular}

Which of the samples most likely had the highest solubility?

A. 1
B. 2
C. 3
D. 4



Answer :

To determine which sample most likely had the highest solubility, we need to analyze the solubility of the samples at different temperatures. Solubility typically increases with temperature. Therefore, higher temperatures generally lead to higher solubilities of substances in water.

Let's look at the temperatures provided for the four samples:

1. Sample 1: Table sugar ([tex]\(C_{12}H_{22}O_{11}\)[/tex]) at 80°C
2. Sample 2: Table sugar ([tex]\(C_{12}H_{22}O_{11}\)[/tex]) at 45°C
3. Sample 3: Table salt ([tex]\(NaCl\)[/tex]) at 55°C
4. Sample 4: Table salt ([tex]\(NaCl\)[/tex]) at 63°C

Next, we will identify the highest temperature among these four samples. The temperatures are:
- 80°C
- 45°C
- 55°C
- 63°C

From these temperatures, the highest temperature is 80°C, which corresponds to Sample 1.

Given that solubility increases with temperature, the sample with the highest temperature (Sample 1: Table sugar at 80°C) most likely had the highest solubility.

Therefore, the sample that most likely had the highest solubility is:

1

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