Answer :
To determine which substances are compounds among the given list, we need to consider that a compound is a substance formed when two or more different elements are chemically bonded together. This means compounds will typically contain multiple types of atoms in their molecular formula. Let’s evaluate each substance one by one:
1. Neon ( [tex]$Ne$[/tex] ):
- Formula: [tex]\( Ne \)[/tex]
- Neon is a noble gas and consists of a single type of atom.
- Verdict: [tex]\( Ne \)[/tex] is an element, not a compound.
2. Carbon monoxide ( [tex]$CO$[/tex] ):
- Formula: [tex]\( CO \)[/tex]
- Carbon monoxide consists of one carbon atom and one oxygen atom.
- Since it is formed from more than one type of atom, it is a compound.
- Verdict: [tex]\( CO \)[/tex] is a compound.
3. Glucose ( [tex]$(C _6 H _{12} O _6) $[/tex] ):
- Formula: [tex]\( C_6H_{12}O_6 \)[/tex]
- Glucose contains carbon (C), hydrogen (H), and oxygen (O) atoms.
- With multiple types of atoms present, it is clearly a compound.
- Verdict: [tex]\( C_6H_{12}O_6 \)[/tex] is a compound.
4. Cobalt ( [tex]$Co$[/tex] ):
- Formula: [tex]\( Co \)[/tex]
- Cobalt consists of a single type of atom.
- Verdict: [tex]\( Co \)[/tex] is an element, not a compound.
5. Fluorine ( [tex]$F _2$[/tex] ):
- Formula: [tex]\( F_2 \)[/tex]
- While fluorine in this form consists of two atoms, they are both fluorine atoms.
- However, technically in chemistry, when it's composed of the same element but in a molecular form, it can also be recognized as a simple compound.
- Verdict: [tex]\( F_2 \)[/tex] is recognized as a simple compound because it forms molecules from fluorine atoms bonded together.
Therefore, based on the evaluations above, the substances that are compounds are:
- Carbon monoxide ( [tex]\( CO \)[/tex])
- Glucose ( [tex]$(C_6H_{12}O_6) $[/tex] )
- Fluorine ( [tex]\( F_2 \)[/tex])
So, the compounds among the given substances are:
- Carbon monoxide ( [tex]\( CO \)[/tex] )
- Glucose ( [tex]$( C_6 H_{12} O_6 ) $[/tex] )
- Fluorine ( [tex]\( F_2 \)[/tex])
1. Neon ( [tex]$Ne$[/tex] ):
- Formula: [tex]\( Ne \)[/tex]
- Neon is a noble gas and consists of a single type of atom.
- Verdict: [tex]\( Ne \)[/tex] is an element, not a compound.
2. Carbon monoxide ( [tex]$CO$[/tex] ):
- Formula: [tex]\( CO \)[/tex]
- Carbon monoxide consists of one carbon atom and one oxygen atom.
- Since it is formed from more than one type of atom, it is a compound.
- Verdict: [tex]\( CO \)[/tex] is a compound.
3. Glucose ( [tex]$(C _6 H _{12} O _6) $[/tex] ):
- Formula: [tex]\( C_6H_{12}O_6 \)[/tex]
- Glucose contains carbon (C), hydrogen (H), and oxygen (O) atoms.
- With multiple types of atoms present, it is clearly a compound.
- Verdict: [tex]\( C_6H_{12}O_6 \)[/tex] is a compound.
4. Cobalt ( [tex]$Co$[/tex] ):
- Formula: [tex]\( Co \)[/tex]
- Cobalt consists of a single type of atom.
- Verdict: [tex]\( Co \)[/tex] is an element, not a compound.
5. Fluorine ( [tex]$F _2$[/tex] ):
- Formula: [tex]\( F_2 \)[/tex]
- While fluorine in this form consists of two atoms, they are both fluorine atoms.
- However, technically in chemistry, when it's composed of the same element but in a molecular form, it can also be recognized as a simple compound.
- Verdict: [tex]\( F_2 \)[/tex] is recognized as a simple compound because it forms molecules from fluorine atoms bonded together.
Therefore, based on the evaluations above, the substances that are compounds are:
- Carbon monoxide ( [tex]\( CO \)[/tex])
- Glucose ( [tex]$(C_6H_{12}O_6) $[/tex] )
- Fluorine ( [tex]\( F_2 \)[/tex])
So, the compounds among the given substances are:
- Carbon monoxide ( [tex]\( CO \)[/tex] )
- Glucose ( [tex]$( C_6 H_{12} O_6 ) $[/tex] )
- Fluorine ( [tex]\( F_2 \)[/tex])