Answer :
To determine how much work done by friction was exerted on the car as it moved down the inclined plane, let's follow a step-by-step process using the given data and the formula for work done by friction:
Step 1: Write down the formula for work done by friction:
[tex]\[ W_f = f \times d \][/tex]
where:
- [tex]\( W_f \)[/tex] is the work done by friction,
- [tex]\( f \)[/tex] is the force,
- [tex]\( d \)[/tex] is the distance.
Step 2: Identify the given values:
- The force [tex]\( f \)[/tex] acting on the car going down the incline is [tex]\( 0.2309 \)[/tex] Newtons.
- The distance [tex]\( d \)[/tex] the car travels is [tex]\( 39 \)[/tex] meters.
Step 3: Plug these values into the formula:
[tex]\[ W_f = 0.2309 \, \text{N} \times 39 \, \text{m} \][/tex]
Step 4: Calculate the work done by friction:
[tex]\[ W_f = 9.0051 \][/tex]
Therefore, the work done by friction exerted on the car as it moved down the inclined plane is [tex]\( 9.0051 \)[/tex] Joules.
The correct answer is:
(B) 9.005
Step 1: Write down the formula for work done by friction:
[tex]\[ W_f = f \times d \][/tex]
where:
- [tex]\( W_f \)[/tex] is the work done by friction,
- [tex]\( f \)[/tex] is the force,
- [tex]\( d \)[/tex] is the distance.
Step 2: Identify the given values:
- The force [tex]\( f \)[/tex] acting on the car going down the incline is [tex]\( 0.2309 \)[/tex] Newtons.
- The distance [tex]\( d \)[/tex] the car travels is [tex]\( 39 \)[/tex] meters.
Step 3: Plug these values into the formula:
[tex]\[ W_f = 0.2309 \, \text{N} \times 39 \, \text{m} \][/tex]
Step 4: Calculate the work done by friction:
[tex]\[ W_f = 9.0051 \][/tex]
Therefore, the work done by friction exerted on the car as it moved down the inclined plane is [tex]\( 9.0051 \)[/tex] Joules.
The correct answer is:
(B) 9.005