Sure, let's look at the chemical reaction first. The balanced equation for the reaction between sulfur dioxide (SO₂) and oxygen (O₂) to form sulfur trioxide (SO₃) is:
[tex]\[ 2 \text{SO}_2 + \text{O}_2 \rightarrow 2 \text{SO}_3 \][/tex]
From this balanced equation, we can see that 2 moles of sulfur dioxide (SO₂) react with 1 mole of oxygen (O₂) to form 2 moles of sulfur trioxide (SO₃).
Here's a step-by-step solution to the problem:
1. Identify the moles of SO₂ given:
You have 3.4 moles of sulfur dioxide (SO₂).
2. Relate the moles of SO₂ to SO₃ using the stoichiometric coefficients from the balanced equation:
The balanced equation shows a 1:1 molar ratio between SO₂ and SO₃ (since 2 moles of SO₂ produce 2 moles of SO₃).
3. Calculate the moles of SO₃ formed:
Given that the molar ratio between SO₂ and SO₃ is 1:1, the number of moles of SO₃ formed will be the same as the number of moles of SO₂ reacted.
Therefore, if 3.4 moles of sulfur dioxide react with excess oxygen gas, 3.4 moles of sulfur trioxide (SO₃) will be formed.
