To determine the name of the element given its electron configuration, we first need to find the total number of electrons in the configuration. The electron configuration provided is:
[tex]\[ 1s^2 \,2s^2 \,2p^6 \,3s^2 \,3p^6 \,4s^2 \,3d^{10} \,4p^6 \,5s^2 \,4d^{10} \,5p^5 \][/tex]
We'll sum the number of electrons in each subshell:
1. 1s^2 contributes 2 electrons.
2. 2s^2 contributes 2 electrons.
3. 2p^6 contributes 6 electrons.
4. 3s^2 contributes 2 electrons.
5. 3p^6 contributes 6 electrons.
6. 4s^2 contributes 2 electrons.
7. 3d^{10} contributes 10 electrons.
8. 4p^6 contributes 6 electrons.
9. 5s^2 contributes 2 electrons.
10. 4d^{10} contributes 10 electrons.
11. 5p^5 contributes 5 electrons.
Now adding these up:
[tex]\[ 2 + 2 + 6 + 2 + 6 + 2 + 10 + 6 + 2 + 10 + 5 = 53 \][/tex]
Thus, the element has 53 electrons.
Next, we identify the element with 53 electrons. The atomic number of an element corresponds to the number of protons, which is equal to the number of electrons in a neutral atom.
Looking at the periodic table, the element with atomic number 53 is iodine (I).
Therefore, the name of the element is:
Iodine
